Suppose you add x liters of pure water to the 10 L of 25% acid solution. The new solution's volume is x + 10 L. Each L of pure water contributes no acid, while the starting solution contains 2.5 L of acid. So in the new solution, you end up with a concentration of (2.5 L)/(x + 10 L), and you want this concentration to be 10%. So we have
and so you would need to add 15 L of pure water to get the desired concentration of acid.
4z+2(z-4)=3z+11 perform indicated multiplication on left side
4z+2z-8=3z+11 combine like terms on left side
6z/-8=3z+11 add 8 to both sides
6z=3z+19 subtract 3z from both sides
3z=19 divide both sides by 3
z=19/3
z=6 1/3
So there is only one solution when z=6 1/3
700•10 is 7000 so
10 times
Answer:
Jerry will have two apples only
4-2=2
Answer:
x=-0.08 and y=2.92
Step-by-step explanation:
123x + 2(x+3) = -4 y = -0.08 + 3
123x + 2x + 6 = -4 = 2.92
125x + 6 = -4
125x = -10
x= -0.08
