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LuckyWell [14K]

3 years ago

15

One evening, Mr. Smith, Sam, and Sydney went to see the Myrtle Beach Pelicans’ Game. They each bought a ticket and a hat that co

st $10 each. How much was each ticket to enter the ballpark?

1 answer:

o-na [289]3 years ago

3 0

Answer:

You can't answer this question without knowing the total amount of money they all had in total.

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Select the best answer for the question. What is 4C?

e-lub [12.9K]

I think it might be c. but im not sure

6 0

3 years ago

Read 2 more answers

A university has ten dormitories for students. All of the dormitories have students of similar ages and offer the same convenien

lina2011 [118]

Answer:

a is correct

Step-by-step explanation:

4 0

3 years ago

Luis wants to buy a skateboard that usually sells for $79.47. All merchandise is discounted by 12%. What is the total cost of th

valentinak56 [21]

79.47 (total cost before sale) - 9.02 (12% off) = 70.45 (total after sale).
70.45 (total after sale) + 6.32 (tax) = $76.77
Hope this helps!!!

7 0

3 years ago

For which value of x is the equation 3x + x = 2x + 24 true?

Lynna [10]

Answer:

D) 12

Step-by-step explanation:

3x+x=2x+24

4x=2x+24

4x-2x=24

2x=24

x=24/2

x=12

4 0

3 years ago

Consider the following hypothesis test.H0:μ1−μ2=0 Ha:μ1−μ2≠0The following results are for two independent samples taken from the

Julli [10]

Answer:

a) $z =\frac{104-106}{\sqrt{\frac{8.4^2}{80} +\frac{7.6^2}{70}}}= -1.53$

b) $p_v =2*P(z$

c) Since the p value is higher than the significance level provided we have enogh evidence to FAIL to reject the null hypothesis and we can't conclude that the true means are different at 5% of significance

Step-by-step explanation:

Information given

$\bar X_{1}= 104$ represent the mean for 1

$\bar X_{2}= 106$ represent the mean for 2

$\sigma_{1}= 8.4$ represent the population standard deviation for 1

$\sigma_{2}= 7.6$ represent the population standard deviation for 2

$n_{1}=80$ sample size for the group 1

$n_{2}=70$ sample size for the group 2

z would represent the statistic

Hypothesis to test

We want to check if the two means for this case are equal or not, the system of hypothesis would be:

H0: $\mu_{1}=\mu_{2}$

H1: $\mu_{1} \neq \mu_{2}$

The statistic would be given by:

$z =\frac{\bar X_1-\bar X_2}{\sqrt{\frac{\sigma^2_1^2}{n_1} +\frac{\sigma^2_2^2}{n_2}}}=$ (1)

Part a

Replacing we got:

$z =\frac{104-106}{\sqrt{\frac{8.4^2}{80} +\frac{7.6^2}{70}}}= -1.53$

Part b

The p value would be given by this probability:

$p_v =2*P(z$

Part c

Since the p value is higher than the significance level provided we have enogh evidence to FAIL to reject the null hypothesis and we can't conclude that the true means are different at 5% of significance

6 0

3 years ago