3 years ago

I NEED HELP PLEASE

Mathematics

1 answer:

sergey [27]3 years ago

7 0

Answer:

on a graph or a number line

Step-by-step explanation:

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PLS HELP DUE TODAY

Gekata [30.6K]

Here we go !!

Since it's a regular pentagon, all it's sides are equal so let's solve for x

$\hookrightarrow \: 3(x - 1) = 5x - 6$

$\hookrightarrow \: 3x - 3 = 5x - 6$

$\hookrightarrow \: 3x - 5x = - 6 + 3$

$\hookrightarrow \: - 2x = - 3$

$\hookrightarrow \: x = \dfrac{ - 3}{ - 2}$

$\boxed{\boxed{x = \dfrac{3}{2} }}$

now let's find the measure of each side, i.e

$\hookrightarrow \: 5x - 6$

$\hookrightarrow \: (5 \times \dfrac{3}{2}) - 6$

$\hookrightarrow \: \dfrac{15}{2} - 6$

$\hookrightarrow \: 7.5 - 6$

$\mathrm{\hookrightarrow \: 1.5 \: units}$

perimeter = 5 × side length ( for a regular pentagon )

$\hookrightarrow \: 1.5 \times 5$

$\boxed{ \boxed{ \: \: \: \: \: \: \: \: 7.5 \: \: units \: \: \: \: \: \: \: }}$

6 0

3 years ago

(a) In 2008 the total number of tickets sold for an athletics meeting was 3136.

skad [1K]

It’s child TO adult. So 17 child tickets were sold

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3 years ago

What is the GCF of 44j^5k^4 and 121j^2k^6?

Leviafan [203]

$44j^5k^4=2^2\cdot11\cdot j^5 \cdot k^4\\ 121j^2k^6=11^2\cdot j^2 \cdot k^6\\\\ \text{gcf}( 44j^5k^4 ,121j^2k^6)=11j^2k^4$

7 0

2 years ago

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Another customer purchases a pack of gum for $1.25 and a candy bad for $1.10, what is yhe total of these two items before tax ?

Rzqust [24]

$1.25
+
$1.10
___
$2.35 because the 5 goes to 0 the 2 to 1 and 1 to 1 which makes $2.35

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3 years ago

Not a question. just wanted to say I'm making a wand and it looks pretty sick

zhannawk [14.2K]

Answer:

oh ok thanks for free points

Step-by-step explanation:

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3 years ago

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***I NEED HELP PLEASE***

I NEED HELP PLEASE