1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
cricket20 [7]
3 years ago
10

Golf balls can be purchased in a 3-pack for $4.95 or a 12-pack for $18.95. Which is the better buy? Which Item cost less per gol

f ball? By how much?
Mathematics
1 answer:
natka813 [3]3 years ago
7 0
I think the better buy would be the 12-pack because the quality of the ball and the brand would determine the price. Golf balls do the same thing, you hit than lose it than buy a whole new pack of balls. The 3-pack cost less because it’s $4.95 and the 12-pack cost $18.95. By $14 much.
You might be interested in
Convert x=-3 to polar equation
jonny [76]
If a point
(
x
,
y
)
is written as
(
r
,
θ
)
in polar coordinates, then
x
=
r
o
s
θ
and
y
=
r
sin
θ
.
As such in polar form equation
x
=
−
3
can be written as
r
cos
θ
=
−
3
or
r
=
−
3
cos
θ
7 0
3 years ago
If an angle of 110º bisected, find the measure of each angle formed?
bekas [8.4K]

Answer:

55°

Step-by-step explanation:

if an angle is bisected, it get divided into two equal angles .

so, each resulting angle will be half of the angle which is bisected.

hence, measure of each angle formed is

110° / 2 = 55°

3 0
3 years ago
Read 2 more answers
Plz help with this word problem
Andreyy89
He will mix some 20% solution and some 70% solution to make 60% solution.

Let x = number of liters of 20% solution.
Let y = number of liters of 70% solution.

He wants to make 50 liters of 60% solution, so

x + y = 50   First Equation

The amount of acid in x amount of 20% solution is 20% of x, or 0.2x
The amount of acid in y amount of 70% solution is 70% of y, or 0.7y
The amount of acid in 50 liters of 60% solution is 60% of 50 liters, or 0.6 * 50 = 30
Now we add the amounts of acid.
0.2x + 0.7y = 30   Second Equation

x + y = 50
0.2x + 0.7y = 30

-0.2x - 0.2y = -10
0.2x + 0.7y = 30
------------------------
           0.5y = 20

y = 40

x + y = 50

x + 40 = 50

x = 10

Answer: He needs 10 liters of 20% solution and 40 liters of 70% solution.
4 0
3 years ago
Read 2 more answers
Use logarithms to solve each equation 2x9/8=111
Illusion [34]
<span>We have this equation:
</span>
2x^{\frac{9}{8}} = 111

and we need to find the value of x.

First of all, we multiply the whole equation for 1/2, so our goal is to isolate x, therefore:

x^{\frac{9}{8}}=\frac{111}{2}
 
Next step we must do is to apply <span>logarithms:
</span>
logx^{\frac{9}{8}} = log(\frac{111}{2})

Next, we have to apply identities and then to solve the equation:

\frac{9}{8}logx = log(\frac{111}{2})
logx =  \frac{8}{9}log(\frac{111}{2})
logx = 1.5504
10^{logx} =  10^{1.5504}

Finally, we have the value of x which was our goal. This is the answer for the question above:

x= 35.5140

7 0
4 years ago
The perimeter of a rectangular pool is 326 M if the length of the pool is 87 M what is its width​
sveta [45]

Half the perimeter is equal to the length plus the width.

326 /2 = 163

Length + width = 163

87 + width = 163

Width = 163 - 87

Width = 76 meters

4 0
3 years ago
Other questions:
  • 82= 2( 1-8p) step by step
    10·1 answer
  • What is the value of the expression shown below if x = 3, y = 6, and z =<br> 4?<br> x² + 3yz
    15·1 answer
  • What is 3 2/5 minus 1 9/10
    14·2 answers
  • CW
    10·1 answer
  • for homework create your own inequality below that represents a real word situation.solve your problem in to two ways , one corr
    6·1 answer
  • The following is the graph of the quadratic parent function. T/F?
    12·1 answer
  • Determine whether the triangles are congruent. Explain your reasoning .
    6·1 answer
  • Help me please!!! Whats the length for w?
    13·2 answers
  • Change 7 5/7 to improper fraction
    14·1 answer
  • Help pls i need help​
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!