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SVEN [57.7K]
3 years ago
6

Need help. Due soon please answer ASAP!

Mathematics
2 answers:
vagabundo [1.1K]3 years ago
7 0
(-6, 12)

(15, -16)

(6,-4)

hope this helps! :-)
IrinaK [193]3 years ago
7 0

Answer:

Step-by-step explanation:

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The answer is
4/12
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33/100
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If i put 2 table spoons of sugar in koolaid how much water should i add.
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Kelly buys a sweater for $16.79 and a pair of pants for $28.49. She pays with a $50 bill. How much change should Kelly get back?
andrew11 [14]
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4 0
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Question 8
Stells [14]

The mean of the data is: 67.1

The median is: 70.5

The mode is: 71

<h3>What is the Mean, Median, and Mode of a Data Set?</h3>
  • The mean = average
  • Mode = data point that appears the most
  • Median = center of the data.

Given, 68, 79, 71, 52, 71, 54, 71, 81, 54, 70:

Mean = (68 + 79 + 71 + 52 + 71 + 54 + 71 + 81 + 54 + 70)/10

Mean = 671/10

Mean = 67.1

Median = (70 + 71)/2 = 70.5

Mode = 71

Learn more about the mean, median, and mode on:

brainly.com/question/14532771

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8 0
2 years ago
(c) what is the probability that at least one adult prefers milk chocolate to dark chocolate?
Schach [20]
Part A:

Given that 47% of adults prefer milk chocolate to dark chocolate, for a random sample of n = 4 adults, the probability that all four adults say that they prefer milk chocolate to dark chocolate is given by

P(4)=(0.47)^4=0.049



Part B:

The probability that exactly two of the four adults say they prefer milk chocolate to dark chocolate is given by

P(2)={ ^4C_2(0.47)^2(1-0.47)^2} \\  \\ =6(0.2209)(0.2809)=0.372



Part C:

The probability that at least one adult prefers milk chocolate to dark chocolate is given by

P(at \ least \ 1)=P(X\geq1) \\  \\ =P(1)+P(2)+P(3)+P(4) \\  \\ =1-P(0)=1-{ ^4C_0(0.47)^0(1-0.47)^4} \\  \\ =1-(0.53)^4=1-0.0789=0.921
6 0
3 years ago
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