How do i solve this

Mathematics

1 answer:

horrorfan [7]4 years ago

8 0

Well angle ABD is a right angle. 90 degrees. And angle CBD is 35 degrees.

So you would just do 90-35 = 55

ABC or x = 55 degrees.

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use the identity below to complete the tasks a^3-b^3=(a-b)(a^2+ab+b^2) when using the identity for the difference of two cubes t

zheka24 [161]

Answer:

see explanation

Step-by-step explanation:

Given that the the difference of cubes is

a³ - b³ = (a - b)(a² + ab + b²)

Given

64 $x^{6}$ - 27 ← a difference of cubes

with a = 4x² and b = 3, thus

= (4x²)³ - 3³

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3 years ago

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Katyanochek1 [597]

Problem 4-25
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7 0

3 years ago

Find the area of a quadrilateral ABCD in which AB = 3 cm, BC = 4 cm, CD = 4 cm, DA = 5 cm and AC = 5 cm.

melamori03 [73]

Answer:

$6+2\sqrt{21}\:\mathrm{cm^2}\approx 15.17\:\mathrm{cm^2}$

Step-by-step explanation:

The quadrilateral ABCD consists of two triangles. By adding the area of the two triangles, we get the area of the entire quadrilateral.

Vertices A, B, and C form a right triangle with legs $AB=3$ , $BC=4$ , and $AC=5$ . The two legs, 3 and 4, represent the triangle's height and base, respectively.

The area of a triangle with base $b$ and height $h$ is given by $A=\frac{1}{2}bh$ . Therefore, the area of this right triangle is:

$A=\frac{1}{2}\cdot 3\cdot 4=\frac{1}{2}\cdot 12=6\:\mathrm{cm^2}$

The other triangle is a bit trickier. Triangle $\triangle ADC$ is an isosceles triangles with sides 5, 5, and 4. To find its area, we can use Heron's Formula, given by: