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dusya [7]
3 years ago
11

How can you tell from a table of values if a relationship is proportional?

Mathematics
1 answer:
dusya [7]3 years ago
4 0
C- in the table every ratio y/x is equal so the relationship is proportional
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Solve the following system of equations<br> 3X +5Y=16<br> 2X+7Y=7
RoseWind [281]

Answer:

equals 56y+3x

Step-by-step explanation:

8 0
3 years ago
3. What % of 100 is 13?
Sedbober [7]

Answer:

To get the solution, we are looking for, we need to point out what we know.

1. We assume, that the number 13 is 100% - because it's the output value of the task.

2. We assume, that x is the value we are looking for.

3. If 13 is 100%, so we can write it down as 13=100%.

4. We know, that x is 100% of the output value, so we can write it down as x=100%.

5. Now we have two simple equations:

1) 13=100%

2) x=100%

where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:

13/x=100%/100%

6. Now we just have to solve the simple equation, and we will get the solution we are looking for.

7. Solution for what is 100% of 13

13/x=100/100

(13/x)*x=(100/100)*x       - we multiply both sides of the equation by x

13=1*x       - we divide both sides of the equation by (1) to get x

13/1=x

13=x

x=13

now we have:

100% of 13=13

Step-by-step explanation:

Have A Wonderful Day !!

5 0
3 years ago
At a large Midwestern university, a simple random sample of 100 entering freshmen in 1993 found that 20 of the sampled freshmen
guajiro [1.7K]

Answer:

The 90% confidence interval for the difference of proportions is (0.01775,0.18225).

Step-by-step explanation:

Before building the confidence interval, we need to understand the central limit theorem and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

p1 -> 1993

20 out of 100, so:

p_1 = \frac{20}{100} = 0.2

s_1 = \sqrt{\frac{0.2*0.8}{100}} = 0.04

p2 -> 1997

10 out of 100, so:

p_2 = \frac{10}{100} = 0.1

s_2 = \sqrt{\frac{0.1*0.9}{100}} = 0.03

Distribution of p1 – p2:

p = p_1 - p_2 = 0.2 - 0.1 = 0.1

s = \sqrt{s_1^2+s_2^2} = \sqrt{0.04^2 + 0.03^2} = 0.05

Confidence interval:

p \pm zs

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

90% confidence level

So \alpha = 0.1, z is the value of Z that has a p-value of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.  

The lower bound of the interval is:

p - zs = 0.1 - 1.645*0.05 = 0.01775&#10;

The upper bound of the interval is:

p + zs = 0.1 + 1.645*0.05 = 0.18225&#10;

The 90% confidence interval for the difference of proportions is (0.01775,0.18225).

6 0
3 years ago
Please help thank youu
rodikova [14]
Y results from something being multiplied by x , and the values are always proportional to one another. Notice that putting these points into a ratio of x-value to y-value results in 1:3 as a simplified version. So, the constant of proportionality is what x is being multiplied by to get y . In this case, it is 3 . PLEASE MARK A THE BRAIN THINGY
8 0
3 years ago
How do I solve for x?
zheka24 [161]
3.) 5x-6=0, Add 6 to either side -> 5x=6, divide each side by 5 -> x=6/5 ---- 4.) x+y/3=5, multiple each side by 3 -> x+y=15, move y to the other side -> x=-y+15
3 0
3 years ago
Read 2 more answers
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