The length of side CD is equal to 11 units.
Given coordinates of rectangle are A(-7,-5), B(-7,6),C(-4,6) ,D(-4,-5)
We are require to find the length of side CD.
Rectangle is a two dimensional figure whose two opposite sides are equal to each other. Distance between two coordinates is the equal to length of a side.
We know that the distance means how far two points are located.
Coordinates of A(-7,-5), B(-7,6),C(-4,6) ,D(-4,-5).
Distance=
where (
are the coordinates of two ends of a line.
CD=![\sqrt{(-5-6)^{2} +(-4+4)^{2} }](https://tex.z-dn.net/?f=%5Csqrt%7B%28-5-6%29%5E%7B2%7D%20%2B%28-4%2B4%29%5E%7B2%7D%20%7D)
=![\sqrt{11^{2}+0^{2} }](https://tex.z-dn.net/?f=%5Csqrt%7B11%5E%7B2%7D%2B0%5E%7B2%7D%20%20%7D)
=![\sqrt{121}](https://tex.z-dn.net/?f=%5Csqrt%7B121%7D)
=11 units.
Hence the length of side CD is 11 units.
Learn more about distance at brainly.com/question/17273444
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Question is wrong as it should be :
Coordinates of rectangle A(-7,-5), B(-7,6),C(-4,6) ,D(-4,-5) and find the length of CD.