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Taya2010 [7]
3 years ago
10

I NeEd HelP COMMENT QuesTIonS

Mathematics
1 answer:
BabaBlast [244]3 years ago
8 0

Answer:

D

Step-by-step explanation:

the x values don't repeat

(14,7,21,28,35)

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Brandon is shopping at Old Navy during a sale. All shorts are $16 each and all t-shirts are $10 each.He has $100 to spend and wo
DaniilM [7]
Let
x = the number of shorts bought
y =  the number of t-shirts bought

A pair of shorts costs $16 and a t-shirt costs $10. Brandom has $100 to spend.
Therefore
16x + 10y ≤ 100
This may be written as
y ≤ - 1.6x + 10                 (1)

Brandon wants at least 2 pairs of shorts. Therefore
x ≥ 2                               (2)

Graph the equations y = -1.6x + 10 and  x = 2.
The shaded region satisfies both inequalities.

Answer:
Two possible solutions are
(a) 3 pairs of shorts and 4 t-shirts,
(b) 4 pairs of shorts and 2 t-shirts.

7 0
3 years ago
An altitude is drawn from the vertex of an isosceles triangle, forming a right angle
romanna [79]

Answer:

  • 54 in

Step-by-step explanation:

Use Pythagorean to find the missing side x of the triangle.

<u>It is a hypotenuse with other sides 18 in and half of 15 in:</u>

  • x = \sqrt{18^2+(15/2)^2} =\sqrt{380.25} =19.5

<u>The perimeter is:</u>

  • P = 2*19.5 + 15 = 54
7 0
2 years ago
major each of the following angles write it measures right weather it is acute ,obtuse, right angle A straight angle or a reflex
Leya [2.2K]

Answer:

i = right angle

ii = obtuse angle

iii = straight angle

iv = obtuse angle

v = acute angle

Step-by-step explanation:

an acute angle is an angle less than 90 degrees

an obtuse angle is an angle more than 90 degrees

a right angle is an angle equivalent to 90 degrees (looks like two straight lines perpendicular)

a straight angle is an angle equivalent to 180 degrees (looks like a straight line)

a reflex angle is an angle greater than 180 degrees

so, ...

i = right angle

ii = obtuse angle

iii = straight angle

iv = obtuse angle

v = acute angle

3 0
2 years ago
Y=-(5)^2=-100 how do I do that
Leona [35]
All you have to use is pemdas and keep y by itself
7 0
3 years ago
The point P(7, −2) lies on the curve y = 2/(6 − x). (a) If Q is the point (x, 2/(6 − x)), use your calculator to find the slope
NARA [144]

Answer:

a) (i) m = 2.22, (ii) m = 2, (iii) m = 2, (iv) m = 2, (v) m = 1.82, (vi) m = 2, (vii) m = 2, (viii) m = 2; b) m \approx 2; c) The equation of the tangent line to curve at P (7, -2) is y = 2\cdot x + 12.

Step-by-step explanation:

a) The slope of the secant line PQ is represented by the following definition of slope:

m = \frac{\Delta y}{\Delta x} = \frac{y_{Q}-y_{P}}{x_{Q}-x_{P}}

(i) x_{Q} = 6.9:

y_{Q} =\frac{2}{6-6.9}

y_{Q} = -2.222

m = \frac{-2.222 + 2}{6.9-7}

m = 2.22

(ii) x_{Q} = 6.99

y_{Q} =\frac{2}{6-6.99}

y_{Q} = -2.020

m = \frac{-2.020 + 2}{6.99-7}

m = 2

(iii) x_{Q} = 6.999

y_{Q} =\frac{2}{6-6.999}

y_{Q} = -2.002

m = \frac{-2.002 + 2}{6.999-7}

m = 2

(iv) x_{Q} = 6.9999

y_{Q} =\frac{2}{6-6.9999}

y_{Q} = -2.0002

m = \frac{-2.0002 + 2}{6.9999-7}

m = 2

(v) x_{Q} = 7.1

y_{Q} =\frac{2}{6-7.1}

y_{Q} = -1.818

m = \frac{-1.818 + 2}{7.1-7}

m = 1.82

(vi) x_{Q} = 7.01

y_{Q} =\frac{2}{6-7.01}

y_{Q} = -1.980

m = \frac{-1.980 + 2}{7.01-7}

m = 2

(vii) x_{Q} = 7.001

y_{Q} =\frac{2}{6-7.001}

y_{Q} = -1.998

m = \frac{-1.998 + 2}{7.001-7}

m = 2

(viii)  x_{Q} = 7.0001

y_{Q} =\frac{2}{6-7.0001}

y_{Q} = -1.9998

m = \frac{-1.9998 + 2}{7.0001-7}

m = 2

b) The slope at P (7,-2) can be estimated by using the following average:

m \approx \frac{f(6.9999)+f(7.0001)}{2}

m \approx \frac{2+2}{2}

m \approx 2

The slope of the tangent line to the curve at P(7, -2) is 2.

c) The equation of the tangent line is a first-order polynomial with the following characteristics:

y = m\cdot x + b

Where:

x - Independent variable.

y - Depedent variable.

m - Slope.

b - x-Intercept.

The slope was found in point (b) (m = 2). Besides, the point of tangency (7,-2) is known and value of x-Intercept can be obtained after clearing the respective variable:

-2 = 2 \cdot 7 + b

b = -2 + 14

b = 12

The equation of the tangent line to curve at P (7, -2) is y = 2\cdot x + 12.

7 0
3 years ago
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