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kvv77 [185]
3 years ago
5

Help me I have time plz!!

Mathematics
1 answer:
Leona [35]3 years ago
6 0

Answer:

D

Step-by-step explanation:

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Mrs.Lohens made curtains for her children’s bedrooms. She used 4 3/4 yards of fabric for Nickys room and 6 5/8 yards for Linda’s
Gelneren [198K]

Answer:

11\frac{3}{8}\ yd

Step-by-step explanation:

we know that

To find out the total yards of fabric used, add up the yards of fabric used for Nickys' room and the yards of fabric used for Linda's room

so

4\frac{3}{4}+6\frac{5}{8}

Convert mixed number to an improper fraction

4\frac{3}{4}\ yd=4+\frac{3}{4}=\frac{4*4+3}{4}=\frac{19}{4}\ yd

6\frac{5}{8}\ yd=6+\frac{5}{8}=\frac{6*8+5}{8}=\frac{53}{8}\ yd

Adds the fractions

\frac{19}{4}+\frac{53}{8}=\frac{2*19+53}{8}= \frac{91}{8}\ yd

Convert to mixed number

\frac{91}{8}\ yd= \frac{88}{8}+ \frac{3}{8}= 11\frac{3}{8}\ yd

6 0
3 years ago
Howard has a scale model of the Statue of Liberty. The model is 15 inches tall. The scale of the model to the actual statue is 1
sergiy2304 [10]

Answer:

Required equation \frac{1}{6.2}=\frac{15}{x}

The height of statue of liberty is 93 meters.

Step-by-step explanation:

Given : Howard has a scale model of the Statue of Liberty. The model is 15 inches tall. The scale of the model to the actual statue is 1 inch : 6.2 meters.

To find : Which equation can Howard use to determine x, the height in meters, of the Statue of Liberty?

Solution :

The model is 15 inches tall.

The scale of the model to the actual statue is 1 inch : 6.2 meters.

Let  x be the height in meters of the Statue of Liberty.

According to question, required equation is

\frac{1}{6.2}=\frac{15}{x}

Cross multiply,

x=15\times 6.2

x=93

Therefore, the height of statue of liberty is 93 meters.

4 0
3 years ago
Suppose the solutions of a homogeneous system of four linear equations in five unknowns are all multiples of one nonzero solutio
Akimi4 [234]

Consider a homogeneous machine of four linear equations in five unknowns are all multiples of 1 non-0 solution. Objective is to give an explanation for the gadget have an answer for each viable preference of constants on the proper facets of the equations.

Yes, it's miles true.

Consider the machine as Ax = 0. in which A is 4x5 matrix.

From given dim Nul A=1. Since, the rank theorem states that

The dimensions of the column space and the row space of a mxn matrix A are equal. This not unusual size, the rank of matrix A, additionally equals the number of pivot positions in A and satisfies the equation

rank A+ dim NulA = n

dim NulA =n- rank A

Rank A = 5 - dim Nul A

Rank A = 4

Thus, the measurement of dim Col A = rank A = five

And since Col A is a subspace of R^4, Col A = R^4.

So, every vector b in R^4 also in Col A, and Ax = b, has an answer for all b. Hence, the structures have an answer for every viable preference of constants on the right aspects of the equations.

8 0
3 years ago
How do you do this please explain
MArishka [77]
What is the lesson? We are aware that the 2 triangles are congruent, they also tell us what the two segments are equal to. Your best is to set up an equation making the segments equal to eachother to find the value of segment WK
6 0
4 years ago
A new fertilizer was applied to the soil of 146 bean plants. 23% showed increased growth. Find the margin of error and 95% confi
USPshnik [31]

Answer:

The significance level for this case would be \alpha=1-0.95=0.05 and the critical value for this case would be:

z_{\alpha/2}=1.96

The margin of error is given by:

ME = z_{\alpha/2} \sqrt{\frac{\hat p (1-\hat p)}{n}}

And replacing we got:

ME = 1.96 \sqrt{\frac{0.23*(1-0.23)}{146}} =0.0683

And the margin of error for this case would be ME = 0.07

Step-by-step explanation:

For this case we have the following dataset given:

n= 146 represent the sample size

\hat p =0.23 represent the estimated proportion of interest

Conf=0.95 represent the confidence level

The significance level for this case would be \alpha=1-0.95=0.05 and the critical value for this case would be:

z_{\alpha/2}=1.96

The margin of error is given by:

ME = z_{\alpha/2} \sqrt{\frac{\hat p (1-\hat p)}{n}}

And replacing we got:

ME = 1.96 \sqrt{\frac{0.23*(1-0.23)}{146}} =0.0683

And the margin of error for this case would be ME = 0.07

4 0
3 years ago
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