Answer:
The speed in of the plane is 115.47 m/sec
Step-by-step explanation:
Given:
Height at which the plane is flying = 6000 m
Angle of elevation at the radar base = 30 Degrees
Angle of elevation at the radar base after one minute = 60 Degrees
To Find:
The Speed of the plane in meter per second = ?
Solution:
Let us use the tangent of the angle to find the distance (d) to a point directly below plane:
<u>when the angle is 30 degrees</u>



d1 = 10392.3 meters
<u>when the angle is 60 degrees</u>



d2 = 3464.1 meters
<u>distance travelled by aircraft in 1 min is </u>
=>d1 - d2
=>0392.3 - 3464.1
= 6928.2 m/min
<u>Now converting to m/sec</u>
=>
=>115.47 m/sec
The graph of the line y = -6 is a horizontal line which passes through the y axis at -6. On the other hand, the graph of the equation, x = 1/6 is a vertical line that passes through the x-axis at 1/6. The intersection of these lines is at a point that is expressed as (1/6, -6).
Answer:
24
Explanation:
V = whl (width times height times length)
V = (2)(3)(4)
V = (6)(4)
V = 24
Answer:
Yes, Fiona is correct
Step-by-step explanation:
WHen the pythagorean theorem is applied to the side lengths (2^2 + 4^2 = c^2), the result for c^2 is 20. The correct answer would be sqrt.20. But Fiona is also correct becuase sqrt of 20 can be simplified to sqrt.4 * sqrt.5; which equals 2*sqrt.5