Which is a unit rate?

Mathematics

2 answers:

ivanzaharov [21]2 years ago

6 0

I think that answer is D I am not 100% sure but sorry if I am wrong

ch4aika [34]2 years ago

6 0

Answer:

18 miles driven in a week

Step-by-step explanation:

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Parallelogram abcd has verticals at A(0,0), B(3,6), C(5,5) and D(2,-1) which conclusion can be made ?

sertanlavr [38]

Answer:

Step-by-step explanation:

when you plot the vertices;

Side AB is perpendicular to side BC

Side AB is parallel to side DC

Side AC is perpendicular to AB

Side AC is perpendicular to DC

Side AC is parallel to side BC

The conclusion made is that ABCD is a rectangle

8 0

2 years ago

Which sequence are geometric? Check all that apply

Ann [662]

Answer:

Step-by-step explanation:

$\text{If}\ a,\ b,\ c,\ d,\ e,\ ...\ \text{is a geometric sequence, then}\ \dfrac{b}{a}=\dfrac{c}{b}=\dfrac{d}{c}=\dfrac{e}{d}=....\\\\\#1\\\\\dfrac{7.5}{10}=0.75\\\dfrac{5.625}{7.5}=0.75\\\dfrac{4.21875}{5.625}=0.75\\\boxed{YES}\\================================\\$

$\#2\\\\\dfrac{40}{160}=\dfrac{1}{4}\\\dfrac{10}{40}=\dfrac{1}{4}\\\dfrac{2.5}{10}=\dfrac{1}{4}\\\boxed{YES}\\================================\\$

$\#3\\\\\dfrac{70}{20}=3.5\\\dfrac{245}{70}=3.5\\\dfrac{857.5}{245}=3.5\\\boxed{YES}\\================================\\$

$\#4\\\\\dfrac{16.5}{13}=\dfrac{165}{130}=\dfrac{33}{26}\\\dfrac{20}{16.5}=\dfrac{200}{165}=\dfrac{40}{33}\neq\dfrac{33}{26}\\\boxed{NO}\\================================\\$

$\#5\\\\\dfrac{5.5}{5}=1.1\\\dfrac{6.05}{5.5}=1.1\\\dfrac{6.655}{6.05}=1.1\\\boxed{YES}\\================================\\$

$\#6\\\\\dfrac{17.1}{16}=1.06875\\\dfrac{18.2}{17.1}=1.0643274..\neq1.06875\\\boxed{NO}$

5 0

3 years ago

The table shows y as a function of x. Suppose a point is added to this table. Which choice gives a point that preserves the func

Hunter-Best [27]

Answer:

Step-by-step explanation:

<u>Functions and Relations</u>

A set of values A can have a relation with another set B as long as at least one element of A has at least one image in B. Functions are special relations where each element of A (the domain of the function) has one and only one image on B (the range of the function).

By looking at the options, we can see that x=9, x=-8, and x=-1 already have defined values in Y, so if we define another value for any of them the relation will stop being a function. The only possible choice to preserve the function is the option

$\boxed{A)\ (-5,7)}$