F = t ⇨ df = dt
dg = sec² 2t dt ⇨ g = (1/2) tan 2t
⇔
integral of t sec² 2t dt = (1/2) t tan 2t - (1/2) integral of tan 2t dt
u = 2t ⇨ du = 2 dt
As integral of tan u = - ln (cos (u)), you get :
integral of t sec² 2t dt = (1/4) ln (cos (u)) + (1/2) t tan 2t + constant
integral of t sec² 2t dt = (1/2) t tan 2t + (1/4) ln (cos (2t)) + constant
integral of t sec² 2t dt = (1/4) (2t tan 2t + ln (cos (2t))) + constant ⇦ answer
Answer C is correct. If angle 1 + angle 2 = 180 degrees then L is parallel to M.
Co interior angles are only supplementary in parallel lines
Answer:
3
Step-by-step explanation:
The 3 is in the tens place representing the number 30.
~theLocoCoco
The answer is the third option, which is:
<span> y = x^2 + 5x + 3
6x + y = −27
The explanation is shown below:
1. When you solve this problem you have the following solution:
x=-6
y=9
x=-5
y=3
2. As you can see the solution corresponds with the graph shown above.
3. You can give value to the variable x of the first equation and values to the x of the second equation, and plot each point obtain. You will see that the parabola and the line, touch each other at the points (-5,3) and (-6,9)</span>
Answer:
A = 760.27
Step-by-step explanation:
The shape presented is a semicircle, and the formula for this is:
A = 
The "
," is the radius, which is half of the diameter, in this case is 44, so all you need to do is divide 44 by 2 = 22, then plug this in:
A = 
A = 
A = 
A = 760.27
