The given equation with t -1 is:
(t – 1)^3 + 6 (t – 1)^2 + 12 (t – 1) + 8
Expand each term before combining for easier visualization:
(t – 1)^3 = t^3 – 3 t^2 + 3t – 1
6 (t – 1)^2 = 6 t^2 – 12 t + 6
12 (t – 1) = 12 t - 12
Then substitute and combine:
-> t^3 – 3 t^2 + 3t – 1 + 6 t^2 – 12 t + 6 + 12 t – 12 + 8
t^3 + 3 t^2 + 3 t + 1 (ANSWER)
Answer:
8
x
−
3
Hope this helps, if it does please give brainliest
First set up the equation 12x-7=4x+9
Get all the x's on one side and number on one side so you have 8x= 16
You get X=2
27 I think..... Oh darn I'm replying to my self
Answer:
2,∞
Step-by-step explanation:
For the range, x2 takes its minimum at x=0 , so putting in x =0 gives y=√x2+4=√0+4=2 therefore making the range [2,∞).
