Mark as brainiest
1) place the compass needle on the external point r.2) make the compass width greater than the distance from r to the given line.
3) draw an arc cutting the given line at two points.
4) mark and label the points of intersection p and q.
5) without changing the compass width, move the compass needle to q and draw another arc below the line crossing the previous arc.
6) move the compass needle to p and make an arc below the line.
7) mark and label the point of intersection s.
8) draw a line from the external point r to the point where the arcs intersect, s.
9) line rs is perpendicular to line pq and passes through the external point r.
x > -3
x < 3
<em><u>-3 < x < 3</u></em>
question didn't mention about "x is real number, or positive, or negative etc".. so we can't say anything more
for example: x can be -2,-1,0,1,2
but if only positive, x can be = 1,2
" " negative, x can be = -1, -2
Hope this helps ^-^
Answer: I would answer but the image is blocked for me- can you type the problem by any chance?
Step-by-step explanation:
Answer: 127^9 so 8594754748609400000
Step-by-step explanation: i’m not sure but 4+6 (7x3)-3 = 127 127^9