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3 years ago

28-8x=15 i don't understand

Mathematics

2 answers:

kolezko [41]3 years ago

8 0

Answer:

1. Rearrange terms

28−8=15

−8+28=152

2. Subtract 28 from both sides of the equation

−8+28=15

−8+28−28=15−28

3. Simplify

• Subtract the numbers

−8= −134

4. Divide both sides of the equation by the same term

−8= −13−8

/−8= −13/−8

5. Simplify

• Cancel terms that are in both the numerator and denominator

• Divide the numbers

=13/8

Step-by-step explanation:

Hope it is helpful....

pantera1 [17]3 years ago

6 0

Answer:

0.375 or 3/ -8

Step-by-step explanation:

28 - 8x = 15

- 8x = 15 - 18

- 8x = 3

x = 3 / - 8

x = - o.375 or 3/ -8

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Eva8 [605]

Answer: $15*(x-3)^2*(x-5)$

Step-by-step explanation:

$\dfrac{x^2-y^2}{x^2-8x+15}\ and\ \dfrac{y^2}{15(x^2-6x+9)} \\\\\\x^2-8x+15=x^2-3x-5x+15=x(x-3)-5(x-3)=(x-3)(x-5)\\\\15(x^2-6x+9)=15*(x-3)^2\\\\LCM (x^2-8x+15,15(x^2-6x+9)\\\\=LCM((x-3)(x-5),15(x-3)^2)\\\\\boxed{=15*(x-3)^2*(x-5)}\\$

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3 years ago

Determine the equation of the line that passes through the points of intersection of the graphs of the quadratic functions f(x)

timofeeve [1]

Answer: $x-2y-2=0$

Step-by-step explanation:

Given :

$f(x) = x^2 - 4 \\ g(x) = - 3x^2 + 2x + 8$

Point of intersection :

$f(x)=g(x)\\x^2-4=-3x^2+2x+8\\4x^2-2x-12=0\\2x^2-x-6=0\\2x^2-4x+3x-6=0\\2x(x-2)+3(x-2)=0\\(x-2)(2x+3)=0\\x=2\,,\,\frac{-3}{2}$

$x=2\,;f(2)=2^2-4=0\\x=\frac{-3}{2}\,; f\left ( \frac{3}{2} \right )=\left ( \frac{3}{2} \right )^2-4=\frac{-7}{4}=-1.75$

So, we have points $\left ( 2,0 \right )\,,\,\left ( -1.5,-1.75\ \right )$

Equation of line passing through two points $\left ( x_1,y_1 \right )\,,\,\left ( x_2,y_2 \right )$ is given by $y-y_1=\frac{y_2-y_1}{x_2-x_1}\left ( x-x_1 \right )$