This is a distance = rate * time problem. The easiest way to solve these is to make a table with the information. Since d= rt, we will set up the table like that:
distance rate time
Mason d 5 t + 8
Nora d 9 t
Let me explain the values in the table. The problem says "...when the swimmers had swam exactly the same distance"; therefore, we put a d there to indicate that, although we have no idea the distance they swam, both distances were the same. The rates are easy; they are self-explanatory. The time could be a little tricky too though. If Mason began swimming 8 seconds earlier than Nora, Nora's time is t and Mason's time is t + 8, which is Nora's time with 8 seconds added to it. Because d = rt, we set up the equations like that: d = 5(t+8), and d = 9t. Because the 2 d's are the same, we set them equal to each other: 5(t+8) = 9t. Simplifying that gives you 5t + 40 = 9t and 40 = 4t and t = 10. Now put that t value of 10 into Mason's time to solve the question they are asking you: t + 8 with the substitution is 10 + 8 = 18. So Mason had been swimming for 18 seconds when they had both swam the same distance.
1 is C because it is more than a 90 degree angle and 2 is d
Answer:
2 / 1
Step-by-step explanation:
19 wouldn’t be reasonable, but it’s a trick question, because it really depends on the weight of the items, but if we don’t know what items they are, then we have to predict that the biggest number would be to much, so I think it’s B, or 19.
Hope this helps.
