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3 years ago

7

Elsa works in the furniture department of a store. She earns a 3.7% commission. If she sells $5200 worth of furniture this week,

how much will she earn in commission?

1 answer:

kenny6666 [7]3 years ago

4 0

The answer should be Elsa will earn $192.4 in commission

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A ball is dropped from a helicopter 100m from the ground. As the ball falls, the magnitude of it's associated velocity is

kotegsom [21]

As the ball falls, the velocity of the ball increases with increase in distance

<h3>Velocity and Motion</h3>

Given Data

Distance = 100m

It should be noted that when an object falls, it velocity increases from zero to the maximum just before it hits the ground from the initial point of lunch.

Note: For a projectile the ball might reach a zero velocity at maximum height

Learn more about velocity here:

brainly.com/question/25705666

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2 years ago

1/5 − 1/3 = what fraction?? − what fraction??

Butoxors [25]

Answer:

-2/15

Step-by-step explanation:

Make them same denominator, which is 15.

1/5=3/15

1/3=5/15

then subtract, and you get -2/15

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3 years ago

What are the subsets of set B =(a. b. c. d)?

noname [10]

Answer:

{},{a},{b},{c},{d},{a,b},{a,c},{a,d},{b,c},{b,d},{c,d},{a,b,c},{a,b,d},{a,c,d},{b,c,d},{a,b,c,d}

Step-by-step explanation:

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3 years ago

What is 0.3 as in the 3 repeating (i forgot what its called) as a simplified fraction?

NARA [144]

0.3333333333... = 1/3

You can just say 0.3 repeating to say 0.33333...

7 0

3 years ago

Finn changes his mind and, from now on, decides to take the normal route to work everyday. On any given day, the time (in minute

Margaret [11]

Answer:

The 33rd percentile of the time it takes Finn to get to work on any given day is 31.04 minutes.

There is a 61.92% probability that Finn took more than 40.5 minutes to get to work on the first day or more than 38.5 minutes to get to work on the second day.

Step-by-step explanation:

This can be solved by the the z-score formula:

On a normaly distributed set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a value X is given by:

$Z = \frac{X - \mu}{\sigma}$

Each z-score value has an equivalent p-value, that represents the percentile that the value X is:

The problem states that:

Mean = 35, so $\mu = 35$

Variance = 81. The standard deviation is the square root of the variance, so $\sigma = \sqrt{81} = 9$ .

Find the 33rd percentile of the time it takes Finn to get to work on any given day. Do not include any units in your answer.

Looking at the z-score table, $z = -0.44$ has a pvalue of 0.333. So what is the value of X when $z = -0.44$ .

$Z = \frac{X - \mu}{\sigma}$

$-0.44 = \frac{X - 35}{9}$

$X - 35 = -3.96$

$X = 31.04$

The 33rd percentile of the time it takes Finn to get to work on any given day is 31.04 minutes.

Over the next 2 days, find the probability that Finn took more than 40.5 minutes to get to work on the first day or more than 38.5 minutes to get to work on the second day.

$P = P_{1} + P_{2}$

$P_{1}$ is the probability that Finn took more than 40.5 minutes to get to work on the first day. The first step to solve this problem is finding the z-value of $X = 40.5$ .

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{40.5 - 35}{9}$

$Z = 0.61$

$Z = 0.61$ has a pvalue of 0.7291. This means that the probability that it took LESS than 40.5 minutes for Finn to get to work is 72.91%. The probability that it took more than 40.5 minutes if $P_{1} = 100% - 72.91% = 27.09% = 0.2709$

$P_{2}$ is the probability that Finn took more than 38.5 minutes to get to work on the second day. Sine the probabilities are independent, we can solve it the same way we did for the first day, we find the z-score of

$X = 38.5$

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{38.5 - 35}{9}$

$Z = 0.39$

$Z = 0.39$ has a pvalue of 0.6517. This means that the probability that it took LESS than 38.5 minutes for Finn to get to work is 65.17%. The probability that it took more than 38 minutes if $P_{1} = 100% - 65.17% = 34.83% = 0.3483$

So:

$P = P_{1} + P_{2} = 0.2709 + 0.3483 = 0.6192$

There is a 61.92% probability that Finn took more than 40.5 minutes to get to work on the first day or more than 38.5 minutes to get to work on the second day.

7 0

4 years ago