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ipn [44]
3 years ago
10

PLEASE ANSWER HONESTLY (PLEASE BE HELPFULL I HAVE BEEN STUCK ON THIS PROBLEM) WILL MARK BRANIEST IF CORRECT. (no links my comput

er is slow and no ctrl c ctrol v if possible

Mathematics
1 answer:
givi [52]3 years ago
3 0

Answer:

Step-by-step explanation:

The formula for Pythagoras's theorem is given by a^2 + b^2 = c^2

Area of a square is given by length * length = L^2

In this case,

The length of the 2 smaller squares are 3 and 4 respectively,

Square A = 3, Square B = 4

Its area (can be counted by the number of small boxes) = 9 and 16 boxes respectively.

The biggest Square C has length of 5 boxes and an area of 25 boxes.

Now Square A + Square B = Square C,

which is 9 + 16 = 25 as shown.

We also know the Area of a square is given by length * length

Thus, re-writing the area as length * length,

We have 3^2 + 4^2 = 5^2,

which checks out with the formula of a^2 + b^2  = c^2.

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Insert two rational number between 1.3 bar and 1.4 bar​
jok3333 [9.3K]

<u>General method</u><u>:</u>

Given numbers are 1.3 bar and 1.4 bar

  • 1.3 bar = 1.333...
  • 1.4 bar = 1.444...

Two rational numbers between them

= 1.3222... and 1.43333...

<u>Mean Method</u><u>:</u>

Let X = 1.333... → → →eqn(i)

since the periodicity is 1 then multiply eqn(i) with 10

⇛10×X = 1.333...×10

⇛10X = 13.333... → → →eqn(ii)

Subtract eqn(ii)-eqn(i)

10X = 13.333...

X = 1.333...

(-)

____________

9X = 12.000...

____________

⇛9X = 12

⇛X = 12/9

⇛X = 4/3

and

Let X = 1.444... → → →eqn(i)

since the periodicity is 1 then multiply eqn(i) with 10

⇛10×X = 1.444...×10

⇛10X = 14.444...→ → →eqn(ii)

Subtract eqn(ii)-eqn(i)

10X = 14.444...

X = 1.444...

(-)

____________

9X = 13.000...

____________

⇛9X = 13

⇛X = 13/9

Now we have 12/9 and 13/9

The rational number between them by mean method (a+b)/2

⇛{(12/9)+(13/9)}/2

⇛(25/9)/2

⇛25/18

and Second rational number

⇛{(12/9)+(25/18)}/2

⇛{(24+25)/18}/2

⇛(49/18)/2

⇛49/36

<u>Answer</u><u>:</u> The two rational numbers between them are 25/18 and 49/36.

<u>also</u><u> read</u><u> similar</u><u> questions</u><u>:</u> INSERT TWO RATIONAL NUMBERS BETWEEN 2 AND 3. How to find them?

brainly.com/question/85169?referrer

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All sides are equal in length.
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You choose 3 bananas from a group of 9. In how many ways can this be done?
alexandr1967 [171]

Assuming the order of selection doesn't matter:

\displaystyle \binom{9}{3}=\dfrac{9!}{3!6!}=\dfrac{7\cdot8\cdot9}{2\cdot3}=84

6 0
4 years ago
FREE POINTS......................................................SEE BELOW......................... Given QT = SR, QV = SU, and
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Answer:

QT is parallel and equal to SR because opposite sides in a parallelogram are equal. QV is equal to SU as triangle QVR and SUT are congruent. QUT and SVR are congruent because the angles and sides of each are similar

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HELP PLEASE!!! 29 points!!!!!!
Levart [38]

Answer:

Step-by-step explanation:

y = 6.5 * x + 5

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4 -> y = 6.5 *4 + 5 = 31

8 0
3 years ago
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