with that template in mind, let's check,
notice, g(x) has a horizontal shift of C/B or +0/2, or just 0, none.
while f(x) has a horizontal shift of C/B or -4/2, or -2, to the right.
so f(x) is really just g(x), but shifted horizontally over 2 units to the right.
Here's how you solve this. So, x+y=2, right? Let's isolate x. x+y-y=2-y. x=2-y. NOW, if x=2-y, in 3x+2y=5, we can REPLACE x with 2-y and use it to solve for y! 3x+2y=5. 3(2-y)+2y=5. (3*2)+(3*-y)+2y=5. 6+(-3y)+2y=5. 6+(-y)=5. 6+(-y)-6=5-6. -y=-1. -y/-1=-1/-1. y=1.
So, if y=1, we can substitute that back into either equation--but let's go with the easier one, x+y=2. x+1=2. x+1-1=2-1. x=1. 1+1=2, so that works; let's check the other equation. 3(1)+2(1)=5. 3+2=5. 5=5. That's correct!
Answer: x=1, y=1
Answer:
does not exist
Step-by-step explanation:
Inserting 2 to both formulas, you get different results. In that cases, a limit does not exist
Answer:
im pretty sure it is .17
Step-by-step explanation:
