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STatiana [176]
3 years ago
6

A train 120cm can pass through a bridge while traveling at 80m/s in 10 s.how many seconds would a train 90m long take if i

Mathematics
1 answer:
alisha [4.7K]3 years ago
5 0

it will take 3600 seconds....

How ?

Answer--

multiply the time value by 60

hope it helps

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What is this 1/4 - (-3/4)= in math
Blababa [14]

Answer:

4/4 = 1

Step-by-step explanation:

5 0
2 years ago
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The bottom of a ladder rests on the ground and the top of the ladder rests against a wall. The ladder forms a 63° angle with the
Eddi Din [679]

Answer:

the one you picked was right.

Step-by-step explanation:

if 63° was the angle and the 12 was the side then "x" will be one the bottom. then you flip the fraction meaning 1/sin63° and x/12 and then multiply 12 on both sides. you will be left with x = 12/sin63°. sorry if that doesn't make sense

5 0
2 years ago
Find the equation of the sphere if one of its diameters has endpoints (4, 2, -9) and (6, 6, -3) which has been normalized so tha
Pavel [41]

Answer:

(x - 5)^2 + (y - 4)^2 + (z - 6)^2 = 14.

(Expand to obtain an equivalent expression for the sphere: x^2 - 10\,x + y^2 - 8\, y + z^2 - 12\, z + 63 = 0)

Step-by-step explanation:

Apply the Pythagorean Theorem to find the distance between these two endpoints:

\begin{aligned}&\text{Distance}\cr &= \sqrt{\left(x_2 - x_1\right)^2 + \left(y_2 - y_1\right)^2 + \left(z_2 - z_1\right)^2} \cr &= \sqrt{(6 - 4)^2 + (6 - 2)^2 + ((-3) - (-9))^2 \cr &= \sqrt{56}}\end{aligned}.

Since the two endpoints form a diameter of the sphere, the distance between them would be equal to the diameter of the sphere. The radius of a sphere is one-half of its diameter. In this case, that would be equal to:

\begin{aligned} r &= \frac{1}{2} \, \sqrt{56} \cr &= \sqrt{\left(\frac{1}{2}\right)^2 \times 56} \cr &= \sqrt{\frac{1}{4} \times 56} \cr &= \sqrt{14} \end{aligned}.

In a sphere, the midpoint of every diameter would be the center of the sphere. Each component of the midpoint of a segment (such as the diameter in this question) is equal to the arithmetic mean of that component of the two endpoints. In other words, the midpoint of a segment between \left(x_1, \, y_1, \, z_1\right) and \left(x_2, \, y_2, \, z_2\right) would be:

\displaystyle \left(\frac{x_1 + x_2}{2},\, \frac{y_1 + y_2}{2}, \, \frac{z_1 + z_2}{2}\right).

In this case, the midpoint of the diameter, which is the same as the center of the sphere, would be at:

\begin{aligned}&\left(\frac{x_1 + x_2}{2},\, \frac{y_1 + y_2}{2}, \, \frac{z_1 + z_2}{2}\right) \cr &= \left(\frac{4 + 6}{2},\, \frac{2 + 6}{2}, \, \frac{(-9) + (-3)}{2}\right) \cr &= (5,\, 4\, -6)\end{aligned}.

The equation for a sphere of radius r and center \left(x_0,\, y_0,\, z_0\right) would be:

\left(x - x_0\right)^2 + \left(y - y_0\right)^2 + \left(z - z_0\right)^2 = r^2.

In this case, the equation would be:

\left(x - 5\right)^2 + \left(y - 4\right)^2 + \left(z - (-6)\right)^2 = \left(\sqrt{56}\right)^2.

Simplify to obtain:

\left(x - 5\right)^2 + \left(y - 4\right)^2 + \left(z + 6\right)^2 = 56.

Expand the squares and simplify to obtain:

x^2 - 10\,x + y^2 - 8\, y + z^2 - 12\, z + 63 = 0.

8 0
3 years ago
What is the exact value for the expression √52-√13+√117? Simplify if possible.
Aleksandr-060686 [28]

√52-√13+√117

sqrt (4*13) - sqrt (13) + sqrt (13*9)

sqrt(4)sqrt(13) -sqrt(13)+sqrt(13)sqrt(9)

2sqrt(13) -sqrt(13)+3sqt(13)

sqrt(13)[2-1+3]

4sqrt(13)

Choice A

8 0
3 years ago
Find 7% of 3.1 trillion
wariber [46]

Answer:217,000,000,000 (or just plain 217000000000)


Step-by-step explanation:7% is 0.07.

0.07 * 3.1 trillion


5 0
3 years ago
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