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Dafna1 [17]
3 years ago
14

Can anyone please solve this question​

Mathematics
1 answer:
Arturiano [62]3 years ago
4 0

Answer:

<acb=90°

inscribed angle from the diameter is 90°

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WHO CAN solve it Please !
Mariulka [41]

Answer:

a) True

<em>      </em>\int\limits^\pi _ {0} \,(\sqrt{1-sin^{2}\alpha  }   )d\alpha =0<em></em>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

<em>Given that the definite integration</em>

<em>            </em>\int\limits^\pi _ {0} \,(\sqrt{1-sin^{2}\alpha  }   )d\alpha<em></em>

<em>we know that the trigonometric formula</em>

<em> sin²∝+cos²∝ = 1</em>

<em>            cos²∝ = 1-sin²∝</em>

<u><em>step(ii):-</em></u>

<em>Now the  integration</em>

<em>         </em>\int\limits^\pi _ {0} \,(\sqrt{1-sin^{2}\alpha  }   )d\alpha = \int\limits^\pi _0 {(\sqrt{cos^{2} \alpha } } \, )d\alpha<em></em>

<em>                                      = </em>\int\limits^\pi _0 {cos\alpha } \, dx<em></em>

<em>Now, Integrating </em>

<em>                                  </em>= ( sin\alpha )_{0} ^{\pi }<em></em>

<em>                                = sin π - sin 0</em>

<em>                               = 0-0</em>

<em>                              = 0</em>

<u><em>Final answer:-</em></u>

<em>      </em>\int\limits^\pi _ {0} \,(\sqrt{1-sin^{2}\alpha  }   )d\alpha =0<em></em>

<em></em>

<em></em>

5 0
2 years ago
Simplify 324 please and thanks
olga55 [171]

Answer:

18

Review the factors of 324 to get the square root which is 18

6 0
3 years ago
What is 941 divided by 8
Sergeu [11.5K]

The answer is below.

941/8 = 177.625.

Answer:


941 divided by 8 equals 117 with a remainder of 5


= 117 R 5

= 117 5/8


7 0
2 years ago
PLEASE HELP ASAP
levacccp [35]

Answer: Its B

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Help<br> I can’t get this ! Please help
Zielflug [23.3K]

Answer:

\sqrt{2^5}

Step-by-step explanation:

First, deal with the product of the two powers of 2 inside the parentheses.

The two factors are powers of 2, so add the exponents.

(2^{\frac{1}{2}} \cdot 2^{\frac{3}{4}})^2 =

= (2^{\frac{1}{2} + \frac{3}{4}})^2

You need a common denominator, 4, to add the fractions.

= (2^{\frac{2}{4} + \frac{3}{4}})^2

= (2^{\frac{5}{4}})^2

Now you have an exponent raised to an exponent. Multiply the exponents and reduce the fraction.

= 2^{\frac{5}{4} \times 2}

= 2^{\frac{10}{4}}

= 2^{\frac{5}{2}}

When a fraction is an exponent, the numerator is an exponent and the denominator is the index of the root. A denominator of 2 means a root index of 2 which means square root.

= \sqrt{2^5}

8 0
1 year ago
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