Answer:
The sum of the first 650 terms of the given arithmetic sequence is 2,322,775
Step-by-step explanation:
The first term here is 4
while the nth term would be ai = a(i-1) + 11
Kindly note that i and 1 are subscript of a
Mathematically, the sum of n terms of an arithmetic sequence can be calculated using the formula
Sn = n/2[2a + (n-1)d)
Here, our n is 650, a is 4, d is the difference between two successive terms which is 11.
Plugging these values, we have
Sn = (650/2) (2(4) + (650-1)11)
Sn = 325(8 + 7,139)
Sn = 325(7,147)
Sn = 2,322,775
log 4 ( a^5 ) - log 4 ( b^6 ) =
log 4 ( a^5 / b^6 )
Use the given functions to set up and simplify
h(8). The answer is −22. Hope this help! :)
Answer:
Step-by-step explanation:
we know that
In the right triangle of the figure XYZ
Applying the Pythagorean Theorem
substitute the given values
square root both sides
Multiply total meters by 100 to get total centimeters:
6 meters x 100 = 600 centimeters.
Now divide total centimeters by 2.554 to get total inches:
600 centimeters / 2.54 = 236.22 inches.
Rounded to the nearest inch = 236 inches.
