Answer:
The sum of the first 650 terms of the given arithmetic sequence is 2,322,775
Step-by-step explanation:
The first term here is 4
while the nth term would be ai = a(i-1) + 11
Kindly note that i and 1 are subscript of a
Mathematically, the sum of n terms of an arithmetic sequence can be calculated using the formula 
Sn = n/2[2a + (n-1)d)
Here, our n is 650, a is 4, d is the difference between two successive terms which is 11.
Plugging these values, we have 
Sn = (650/2) (2(4) + (650-1)11)
Sn = 325(8 + 7,139)
Sn = 325(7,147)
Sn = 2,322,775
 
        
             
        
        
        
log 4 ( a^5 ) - log 4 ( b^6 ) = 
log 4 ( a^5 / b^6 )
 
        
             
        
        
        
Use the given functions to set up and simplify 
h(8). The answer is −22. Hope this help! :)
        
                    
             
        
        
        
Answer:

Step-by-step explanation:
we know that
In the right triangle of the figure XYZ
Applying the Pythagorean Theorem

substitute the given values



square root both sides

 
        
             
        
        
        
Multiply total meters by 100 to get total centimeters:
6 meters x 100 = 600 centimeters.
Now divide total centimeters by 2.554 to get total inches:
600 centimeters / 2.54 = 236.22 inches.
Rounded to the nearest inch = 236 inches.