1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Marat540 [252]
3 years ago
8

A coach can purchase 9 hockey goals for $4,050 or 3 goals for $1,575 how much did each goal cost

Mathematics
2 answers:
coldgirl [10]3 years ago
6 0
525 my guy is the answerrr
ki77a [65]3 years ago
3 0

Answer:

4050/9 = $450.00 each

1573/3 = $524.33 each

You might be interested in
2765÷9 in long division​
Kruka [31]

9\sqrt{2765}         and the total is 307.222222

6 0
3 years ago
in germany, VAT is at 19% Jeremy buys a calculator in germny for €58.31 This price includes VAT Find the amount of VAT paid by
Len [333]

We can use this equation to solve this problem:

<span>t=p+<span>(p⋅r)</span></span>

Where:

t is the total price paid: 58.31 for this problem

p is the price before taxes: What we are solving for in this problem.

r is the tax or VAT rate: 19% for this problem. "Percent" or "%" means "out of 100" or "per 100", Therefore 19% can be written as <span>19100</span> or 0.19.

Substituting and solving for p gives:

<span>58.31=p+<span>(p⋅0.19)</span></span>

<span>58.31=1p+0.19p</span>

<span>58.31=<span>(1+0.19)</span>p</span>

<span>58.31=1.19p</span>

<span><span>58.311.19</span>=<span><span>1.19p</span>1.19</span></span>

<span>49=<span><span>1.19p</span>1.19</span></span>

<span>49=p</span>

<span>p=49</span>

Now, we can find how much the VAT was by taking 19% of 49:

<span>19%×49=0.19×49=9.31</span>

Another was to solve this is to subtract the price without the tax or VAT from the total price giving:

<span>58.31−49=<span>9.31</span></span>

4 0
3 years ago
Read 2 more answers
I need help finding the mean, median, and mode(s) I need help with number 7
natta225 [31]

Answer:

the mean is 57.5 the median is 44.5 and the mode is 47

Step-by-step explanation:

the mode is 47 cuz it appeared twice. the median is 57.5 bc 47+147+24+47+38+42=345 and 345/6 is 57.5

7 0
3 years ago
(2<br> 2X 2<br> −3 ÷ 2<br> 5<br> )<br> 2 =
Pavlova-9 [17]

Answer

Extract form = 2194 /25

Decimal form =87.76

4 0
3 years ago
What is most likely true about the melting times of these two types of chocolates
wel

Answer:

"After 64 seconds, ABOUT HALF of the brands of milk chocolate are LIKELY  to melt and NONE of the brands of Dark Chocolate are likely to melt"

Step-by-step explanation:

The right answer is

"After 64 seconds, ABOUT HALF of the brands of milk chocolate are LIKELY  to melt and NONE of the brands of Dark Chocolate are likely to melt"

We can easily check this solution by seeing the time it took for each chocolate to melt in the attached picture.

After 64 seconds have passed, half of the brands of milk chocolate had already melted, but the dark chocolate time starts after 200s

7 0
3 years ago
Other questions:
  • The Mississippi River flows at a rate of 2 miles per hour. If Eduardo floats
    8·1 answer
  • What is the value of x in the question 5/8=x/52
    11·1 answer
  • A box with a square base and no top is to be made from a square piece of carboard by cutting 7 in. squares from each corner and
    6·1 answer
  • Please help on 10 11 and 12
    7·1 answer
  • When the sun shines at a 60° angle to the ground, Talisa's shadow is 36 inches long.
    13·2 answers
  • If the longest side of a triangle is 12 inches, what must be true about the lengths of the remaining sides?
    12·1 answer
  • Samuel's exit ticket is correct, because he multiplied both sides of the equation by seven, using the Multiplication Property of
    7·1 answer
  • Calculate the amount to which $30 000 will grow in 4 years if it is invested at 5.6% p.a
    6·1 answer
  • Solve for the missing side length for the triangle below
    6·1 answer
  • Calculate the value of x and give reason.
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!