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Agata [3.3K]
3 years ago
9

Steps ! 2(x + 4) = 4x + 3 - 2x + 5

Mathematics
1 answer:
fomenos3 years ago
6 0

Step-by-step explanation:

2x + 8 = 4x + 3 - 2x + 5

2x - 4x + 2x = 3 +5 -8

0 = 0

x = 0

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Factor the following expression. 36y - 12
Over [174]

Hey there!


36y - 12


FIRST LOOK AT THE GCF (Greatest Common Factor)


36y: 1, 2, 3, 4, 6, 9, 12, 18, 36, and y


12: 1, 2, 3, 4, 6, and 12


GCF: 12


So, 12 would most likely be number before you make your parentheses


12(?y - 1)


The numbers in your original equation both share 3 & -1


So, therefore the factor form of your equation should be: 12(3y - 1)


Answer: 12(3y - 1)


Good luck on your assignment & enjoy your day!


~Amphitrite1040:)

7 0
2 years ago
Read 2 more answers
Please Help with a Quiz RN????
miv72 [106K]
Numerator is 57. denominator is 78 therefore, the fraction is numerator/denominator (to the nearest tenth) = 73.1%
3 0
3 years ago
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The expression (x-6)2is equivalent to
Marizza181 [45]

(x - 6) * 2

I'm assuming this is the expression that you typed out, if it isn't, please let me know in the comments :)

Use the distributive property:

= 2(x) - 2(6)

Multiply and simplify

= 2x - 12

This should be the expression that is equivalent to the original. Let me know if you need any clarifications, thanks!

5 0
3 years ago
Which expression is equivalent to 5^3√6c+7^3√6c, if c ≠ 0
scZoUnD [109]

Answer:

Option C

Step-by-step explanation:

complete question

A. 35[3]6cB. 12[3]12cC. 12[3]6cD.72c

The given equation can be written as

5^3√6c+7^3√6c

5 * \sqrt{3 *3*2c} + 7 * \sqrt{3 *3*2c}

5 * 3 *\sqrt{2c} + 7 * 3  *\sqrt{2c}

15  *\sqrt{2c} + 21 *\sqrt{2c}

36 *\sqrt{2c}

12 [3]*\sqrt{2c}

Option C is correct

4 0
2 years ago
Given $a \equiv 1 \pmod{7}$, $b \equiv 2 \pmod{7}$, and $c \equiv 6 \pmod{7}$, what is the remainder when $a^{81} b^{91} c^{27}$
Blizzard [7]
\begin{cases}a\equiv1\pmod7\\b\equiv2\pmod7\\c\equiv6\pmod7\end{cases}

a^{81}\equiv1^{81}\equiv1\pmod7

b^{91}\equiv2^{91}\pmod7

2^{91}\equiv(2^3)^{30}\times2^1\equiv8^{30}\times2\pmod7
8\equiv1\pmod7
2\equiv2\pmod7
\implies2^{91}\equiv1^{30}\times2\equiv2\pmod7

c^{27}\equiv6^{27}\pmod7

6^{27}\equiv(-1)^{27}\equiv-1\equiv6\pmod7

\implies a^{81}b^{91}c^{27}\equiv1\times2\times6\equiv12\equiv5\pmod7
6 0
3 years ago
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