Answer:


Since the calculated values is lower than the critical value we have enough evidence to reject the null hypothesis at the significance level of 2.5% and we can say that the true mean is lower than 36 years old
Step-by-step explanation:
Data given
represent the sample mean
represent the sample standard deviation
sample size
represent the value that we want to test
represent the significance level for the hypothesis test.
t would represent the statistic (variable of interest)
represent the p value for the test (variable of interest)
System of hypothesis
We need to conduct a hypothesis in order to check if the true mean is less than 36 years old, the system of hypothesis would be:
Null hypothesis:
Alternative hypothesis:
The statistic is given by:
(1)
And replacing we got:
Now we can calculate the critical value but first we need to find the degreed of freedom:

So we need to find a critical value in the t distribution with df =21 who accumulates 0.025 of the area in the left and we got:

Since the calculated values is lower than the critical value we have enough evidence to reject the null hypothesis at the significance level of 2.5% and we can say that the true mean is lower than 36 years old
2/9 + 1/3 + 2/3
2/9 + 3/9 + 6/9
(2 + 3 + 6) /9
11/9
Answer:

Step-by-step explanation:
Given equation:

Cube root both sides:
![\implies \sqrt[3]{p^3}= \sqrt[3]{\dfrac{1}{8}}](https://tex.z-dn.net/?f=%5Cimplies%20%5Csqrt%5B3%5D%7Bp%5E3%7D%3D%20%5Csqrt%5B3%5D%7B%5Cdfrac%7B1%7D%7B8%7D%7D)
![\implies p= \sqrt[3]{\dfrac{1}{8}}](https://tex.z-dn.net/?f=%5Cimplies%20p%3D%20%5Csqrt%5B3%5D%7B%5Cdfrac%7B1%7D%7B8%7D%7D)
![\textsf{Apply exponent rule} \quad \sqrt[n]{a}=a^{\frac{1}{n}}:](https://tex.z-dn.net/?f=%5Ctextsf%7BApply%20exponent%20rule%7D%20%5Cquad%20%5Csqrt%5Bn%5D%7Ba%7D%3Da%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D%3A)





Rewrite 8 as 2³:



Simplify:


