During gym class, Alexis played dodgeball for 34 hour.

A fair, twenty-faced die has 19 of its faces numbered from 1 through 19 and has one blank face. Another fair, twenty-faced die h

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I dont know but search it up

3 0

2 years ago

A sample of 100 workers located in Atlanta has an average daily work time of 6.5 hours with a standard deviation of 0.5 hours. A

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Answer:

$t=\frac{6.5-6.7}{\sqrt{\frac{0.5^2}{100}+\frac{0.7^2}{110}}}}=-2.398$

$df = n_1 +n_2 -2= 100+110-2= 208$

Since is a bilateral test the p value would be:

$p_v =2*P(t_{208}$

Comparing the p value with the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we can reject the null hypothesis, and we have significant differences between the two groups at 5% of significance.

Step-by-step explanation:

Data given and notation

$\bar X_{1}=6.5$ represent the sample mean for Atlanta

$\bar X_{2}=6.7$ represent the sample mean for Chicago

$s_{1}=0.5$ represent the sample deviation for Atlanta

$s_{2}=0.7$ represent the sample standard deviation for Chicago

$n_{1}=100$ sample size for the group Atlanta

$n_{2}=110$ sample size for the group Chicago

t would represent the statistic (variable of interest)

$\alpha=0.01$ significance level provided

Develop the null and alternative hypotheses for this study?

We need to conduct a hypothesis in order to check if the meanfor atlanta is different from the mean of Chicago, the system of hypothesis would be:

Null hypothesis: $\mu_{1}=\mu_{2}$

Alternative hypothesis: $\mu_{1} \neq \mu_{2}$

Since we don't know the population deviations for each group, for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}}$ (1)

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Calculate the value of the test statistic for this hypothesis testing.

Since we have all the values we can replace in formula (1) like this:

$t=\frac{6.5-6.7}{\sqrt{\frac{0.5^2}{100}+\frac{0.7^2}{110}}}}=-2.398$

What is the p-value for this hypothesis test?

The degrees of freedom are given by:

$df = n_1 +n_2 -2= 100+110-2= 208$

Since is a bilateral test the p value would be:

$p_v =2*P(t_{208}$

Based on the p-value, what is your conclusion?

Comparing the p value with the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we can reject the null hypothesis, and we have significant differences between the two groups at 5% of significance.

3 0

3 years ago

Read 2 more answers

HELP PLEASE and help me understand

const2013 [10]

When subtracting a number from a negative (like question one) the subtraction sign will now be an addition sign.

1.

6-(-7)=13

For question 2, its simple subtraction. If you subtract a negative from positive, it'l be a negative.

2.

-3 - 3= -6

3.

-15 - 23 = -38

Now we combine my previous explanations. Subtracting a negative from a negative will be like adding (like in question 4)

4.

-9 - (-5)= -4

5.

5 - (-15)=20

6.

78-(-17)=95

Extra Info:

When adding a number (doesnt matter if positive or negative) to a negative it will turn into subtraction.

Examples:

6+(-9)=-3

-9+(-9)= -18

4 0

3 years ago

Structions: In each sentence, write the correct form of the adverb shown in parentheses. Then write a sentenc

Nana76 [90]

Answer:

Step-by-step explanation:

8 0

2 years ago

Cara has $25 to buy dry pet food a pound of dog food costs $2 and treats are $1 apiece if she buys 9 pounds of food the greatest

zzz [600]

Cost of each pound of dog food = $2 .

Total cost of 9 pounds of dog food = 9 * 2 = $18.

Let us assume number of treats she can buy = t.

Cost of each treat = $1.

Cost of t number of treats = 1*t = 1t .

Total money Cara has = $25.

We can setup an inequality as,

Total cost of dog food + total cost of t number of treats ≤ 25.

18 + 1t ≤ 25.

Subtracting 18 from both sides, we get

18 + 1t -18 ≤ 25-18.

1t ≤ 7 or t ≤ 7.

So, she can purchase 7 or less treats.

5 0

2 years ago