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den301095 [7]
2 years ago
15

Please help. Is algebra. PLEASE HELP NO LINKS OR FILES. I don't want links.

Mathematics
1 answer:
alexandr1967 [171]2 years ago
7 0

9514 1404 393

Answer:

  9n^4

Step-by-step explanation:

The divisor and quotient can be interchanged to find the divisor:

  \dfrac{18n^6+27n^5-36n^4}{2n^2+3n-4}=\boxed{\text{Blank 1}}

Such division is carried out by first finding the quotient of the highest-degree terms:

  \dfrac{18n^6}{2n^2}=\dfrac{18}{2}n^{6-2}=9n^4

This value is used to multiply the denominator and subtract that product from the numerator to find the new numerator. The new numerator is zero, so the value that goes in Blank 1 is ...

  9n^4

_____

The attachment shows the long division.

You might be interested in
The Sunny Days Apartment building has a cylindrical, above ground pool in the yard. The radius of the pool is 2 times its height
garik1379 [7]

9514 1404 393

Answer:

  6.2 ft

Step-by-step explanation:

The volume of a cylinder is given by ...

  V = πr²h

Here, we have r=2h and V=3000 ft³. Putting these numbers into the formula and solving for h, we get ...

  3000 ft³ = π(2h)²h

  (3000 ft³)/(4π) = h³ . . . . . divide by the coefficient of h³

  h = ∛(750/π) ft ≈ 6.2 ft

The pool is about 6.2 feet deep.

3 0
2 years ago
Between which pair of numbers is the exact product of 379 and 8?
AnnZ [28]
The product of 379 and 8 is 3,032.

It's between (any number less than 3,032) and (any number greater than 3,032).

I guess if this is an <em>estimation </em>exercise, you could say that it's between
(8 x 300) and (8 x 400), or 2,400 and 3,200. 
5 0
3 years ago
Situation 1. ROCKET RIDE.
Daniel [21]
B beacuse it’s 173 thanks very much
7 0
3 years ago
Find how many six-digit numbers can be formed from the digits 2, 3, 4, 5, 6 and 7 (with repetitions), if:
Goshia [24]

Answer:

case 1 = 2592

case 2 =  729

case 1 + case 2 =  2916

(this is not a direct adition, because case 1 and case 2 have some shared elements)

Step-by-step explanation:

Case 1)

6 digits numbers that can be divided by 25.

For the first four positions, we can use any of the 6 given numbers.

For the last two positions, we have that the only numbers that can be divided by 25 are numbers that end in 25, 50, 75 or 100.

The only two that we can create with the numbers given are 25 and 75.

So for the fifth position we have 2 options, 2 or 7,

and for the last position we have only one option, 5.

Then the total number of combinations is:

C = 6*6*6*6*2*1 = 2592

case 2)

The even numbers are 2,4 and 6

the odd numbers are 3, 5 and 7.

For the even positions we can only use odd numbers, we have 3 even positions and 3 odd numbers, so the combinations are:

3*3*3

For the odd positions we can only use even numbers, we have 3 even numbers, so the number of combinations is:

3*3*3

we can put those two togheter and get that the total number of combinations is:

C = 3*3*3*3*3*3 = 3^6 = 729

If we want to calculate the combinations togheter, we need to discard the cases where we use 2 in the fourth position and 5 in the sixt position (because those numbers are already counted in case 1) so we have 2 numbers for the fifth position and 2 numbers for the sixt position

Then the number of combinations is

C = 3*3*3*3*2*2 = 324

Case 1 + case 2 = 324 + 2592 = 2916

4 0
3 years ago
3/4, 4/5, 7/8, 9/11, 5/6<br>can they be simplified? give your reasons below.​
Bad White [126]
They cannot be simplified
4 0
2 years ago
Read 2 more answers
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