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Sav [38]
3 years ago
11

Can a triangle have side lengths of 12 feet, 6 feet, 3 feet? HURRY PLZ!!?

Mathematics
2 answers:
Nookie1986 [14]3 years ago
6 0

Answer:

No it cannot.

Step-by-step explanation:

It requires certain relationships between the lengths of the sides of a triangle. One cannot simply take three random line segments and form a triangle. The line segments have to satisfy the triangle inequality theorems. Other theorems that define relationships between the sides of a triangle are the Pythagorean theorem and the law of cosines.

Masteriza [31]3 years ago
3 0

Answer:

Step-by-step explanation:

yes

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Find the value of below algebriac expression for x=2,y=-1 and z=2 i. 4x2−3y2+5z24x2−3y2+5z2 ii. 3x3−2x(4yz+5x2)3x3−2x(4yz+5x2) i
Advocard [28]

Answer:

i. 33

ii. 1488

iii. 65

Step-by-step explanation:

i. 4x² − 3y² + 5z²

Putting the values x=2, y=-1 and z=2

4(2)² − 3(-1)² + 5(2)²

4×4 − 3×(1)² + 5×(4)

(16) -  (3×1) + (20)

16 -  3+ 20

36 - 3

33

ii. 3x³ − 2x(4yz+5x²)

Putting the values x=2, y=-1 and z=2

[3(2)³ − 2×2(4×(-1)×2 + 5×(2)²)]

[3(8)³ − 2×2(-8 + 5×4)]

[3 ×512 -  2×2(-8 +20)]

[1536 - 4(12)]

[1536 - 48]

1488

iii. 1−4x(yz+3xy)

Putting the values x=2, y=-1 and z=2

[1 - 4 × 2((-1)×2 + 3×2×(-1))]

[1- 8(-2 + (-6))]

[1- 8 (-2 -6)]

[1 - 8(-8)]

[1 +64]

65

8 0
3 years ago
Complete the number patterns <br><br> 1. 1,3,6,10,15,21,__,__<br><br> 2. 1,3,7,13,21, __,__
sweet-ann [11.9K]
23,26...................
5 0
3 years ago
Read 2 more answers
When lines intersect in one place, what are they called?
Deffense [45]
Independent
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7 0
3 years ago
Read 2 more answers
21. What must be added to -9 to have a sum of 20?
Inga [223]

Answer:

21C

22D

23B

24C

25A

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
A biology test is worth 100 points and has 36 questions.
Ad libitum [116K]

Answer:

(a) 7 essays and 29 multiple questions

(b) Your friend is incorrect

Step-by-step explanation:

Represent multiple choice with M and essay with E.

So:

M + E= 36 --- Number of questions

2M + 6E = 100 --- Points

Solving (a): Number of question of each type.

Make E the subject of formula in M + E= 36

E = 36 - M

Substitute 36 - M for E in 2M + 6E = 100

2M + 6(36 - M) = 100

2M + 216 - 6M = 100

Collect Like Terms

2M - 6M = 100 - 216

-4M = - 116

Divide both sides by -4

M = \frac{-116}{-4}

M = 29

Substitute 29 for M in E = 36 - M

E = 36 - 29

E = 7

Solving (b): Can the multiple questions worth 4 points each?

It is not possible.

See explanation.

If multiple question worth 4 points each, then

2M + 6E = 100 would be:

4M + xE = 100

Where x represents the number of points for essay questions.

Substitute 7 for E and 29 for M.

4 * 29 + x * 7 = 100

116 + 7x = 100

Subtract 116 from both sides

116-116 + 7x = 100 -116

7x = 100-116

7x = -16

Make x the subject

x = -\frac{16}{7}

Since the essay question can not have worth negative points.

Then, it is impossible to have the multiple questions worth 4 points

<em>Your friend is incorrect.</em>

6 0
2 years ago
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