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3 years ago

If m<BDC = 20, m arc AB = 140, and marc CD = 120, find m<1.

Mathematics

2 answers:

rosijanka [135]3 years ago

7 0

Answer:

Step-by-step explanation:

lara [203]3 years ago

4 0

Answer:

ljfldnjkafkjagfbkg bkj hbsfgjhg .

Step-by-step explanation:

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Three people pull simultaneously on a stubborn donkey. Jack pulls directly ahead of the donkey with a force of 90.5 N , Jill pul

Radda [10]

Answer:

Fn= 174.9 N : Magnitude of the net force the people exert on the donkey.

Step-by-step explanation:

We find the components of the forces in x-y-z

Force of Jack in z =F₁z=90.5 N in direction (+z)

Force of Jill in x = F₂x= -82.3*cos45°= - 58.19 N (-x)

Force of Jill in y =F₂y=-82.3*sin45°= + 58.19 N (+y)

Force of Jane in x =F₃x=125*cos45°= + 88.4 N (+x)

Force of Jane in y =F₃y=125*sin45°= + 88.4 N (+y)

Calculating of the components of the net force the people exert on the donkey.

Fnx= F₂x+F₃x=( - 58.19+ 88.4 )N=30.2N (+x)

Fny= F₂y+F₃y=( 58.19+88.4 ) = 146.59 N (+y)

Fnz =F₁z=90.5 N (+z)

Calculating of the magnitude of the net force the people exert on the donkey.

$F_{n} =\sqrt{(F_{nx})^{2}+(F_{ny}) ^{2} +(F_{nz}) ^{2} }$

$F_{n} =\sqrt{(30.2)^{2}+( 146.59) ^{2} +(90.5) ^{2} }$

$F_{n} = 174.9 N$

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3 years ago

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre

tatiyna

Answer:

The product of $3a^2.2a^3\\$ is $6a^6$

Step-by-step explanation:

We need to find the product of $3a^2.2a^3\\$

Using the exponent rule: $a^m. a^n = a^{m*n}$

So,

$3a^2.2a^3\\$

Applying above rule:

$3.2 (a^{2*3})\\$

$6a^6$

So, the product of $3a^2.2a^3\\$ is $6a^6$

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3 years ago

PLEASE HELP!!!!!!!!!!!!!!!!!!!!!

kakasveta [241]

Answer:

true

Step-by-step explanation:

the powers are first, they are in alphebetical order

<h2><em><u>xoxo, </u></em></h2><h2><em><u>your highness...</u></em></h2>

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3 years ago

Read 2 more answers

If f(x) = 2x-7, what is the equation for f^-1(x)?

quester [9]

F= -1
2x (-1)-7= -2-7= -9

8 0

3 years ago

A right cone has radius 9cm and slant height 12cm. The radius and slant height are both multiplied by 2/3. Which of the followin

Olegator [25]

Answer:

<em>The surface area is multiplied by 4/9.</em>

Step-by-step explanation:

<u>Surface Area of a Cone</u>

Being r the radius and l the slant height of a cone, then its surface area is

$SA=\pi r^2+\pi r l$

Now let's think both the radius and the slant height are multiplied by the same factor k, i.e.

r'=kr

l'=kl

The new surface area is

$SA'=\pi r'^2+\pi r' l'=\pi (kr)^2+\pi \cdot kr\cdot kl=k^2\pi r^2+k^2\pi rl$

$SA'=k^2(\pi r^2+\pi rl)=k^2\cdot SA$

The new surface area is the $k ^2$ times original SA. Since k=2/3, then

$SA'=4/9\ SA$

The surface area is multiplied by 4/9.

6 0

3 years ago

If m<BDC = 20, m arc AB = 140, and marc CD = 120, find m<1.​

If m<BDC = 20, m arc AB = 140, and marc CD = 120, find m<1.