Answer:
The correct pseudocode to find the records of all citizens over the age of 50 is IF(age > 50).
OR EACH item IN citzlist
{
WHILE(not end of citzlist)
{
IF(age > 50)
{
DISPLAY(name)
}
}
}
If this is run, it will bring out all the names of the citizen who are over the age of 50 in the list.
Explanation:
Answer:
True
Explanation:
Using the t-distribution table, the critical value for a one-tailed test with 6 degrees of freedom and 0.05 significance level is 2.447
Conclusion:
Reject the null hypothesis because the test statistic 2.045 is less than the critical value 2.447
Answer:
it would be nice if you gave some form of info here
Explanation:
in other words without information no help aka I'm slow and just need points
Answer:
This article shows how to use regex to remove spaces in between a String.
A string with spaces in between.
String text = "Hello World Java.";
We want to remove the spaces and display it as below:
Hello World Java.
1. Java regex remove spaces
In Java, we can use regex \\s+ to match whitespace characters, and replaceAll("\\s+", " ") to replace them with a single space.
Regex explanation.
`\\s` # Matches whitespace characters.
+ # One or more
StringRemoveSpaces.java
package com.mkyong.regex.string;
public class StringRemoveSpaces {
public static void main(String[] args) {
String text = "Hello World Java.";
String result = text.replaceAll("\\s+", " ");
System.out.println(result);
}
}
Output
Terminal
Hello World Java.
