Answer:
modulation
Explanation:
Modulation is the procedure of encoding data into electrical signals for transmission through a media. For transmission, binary information, denoted by a sequence of ones and zeros, should be translated to analog or digital electrical signals. The method converts data into electrical signals suited for transmission is known as modulation. Digital modulation is the transmission of binary signals zeroes and ones.
Random integer, in this case betweeen 1 and 100
Answer:
The four types of maintenance in IT are given as:
Preventive maintenance: It is the important part to facilitates the management system and it should be designed carefully o prevent them from failure. the main aim of preventive maintenance is to successfully establish the design to improve the system performance.
Corrective maintenance: It basically refers to the changes made to repair the defects in the implementation and designing of the system. It is usually performed after the failure occur in the equipment. It also increased overall productivity of the system.
Perfective maintenance: It basically improve the performance of the system, efficiency and maintainability. This type of maintenance are initiated by the IT department.
Adaptive maintenance: It involves the implementation changes in the system to increase its functionality. It basically improve its efficiency and increase its capability. It is less urgent than corrective maintenance.
B) output device
bc you’re using them to listen to something
<u>Answer:</u>
a) First, we need to determine the pipeline stage amounting to the maximum time. In the given case, the maximum time required is 2ns for MEM. In addition, the pipeline register delay=0.1 ns.
Clock cycled time of the pipelined machine= max time+delay
=2ns+0.1 ns
=2.1 ns
b) For any processor, ideal CPI=1. However, since there is a stall after every four instructions, the effective CPI of the new machine is specified by:
c) The speedup of pipelined machine over the single-cycle machine=avg time per instruction of single cycle/avg time per instruction of pipelined.
Single cycle processor:
CPI=1
Clock period=7 ns
Pipelined processor:
Clock period=2.1 ns
CPI=1.25
Therefore, speedup=
=7/2.625
= 2.67
d) As the number of stages approach infinity, the speedup=k where k is the number of stages in the machine.
