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maw [93]
3 years ago
12

Solve5(2x-3) = 3(x+4)

Mathematics
2 answers:
dusya [7]3 years ago
6 0
5(2x-3) = 3(x+4)\\
10x-15=3x+12\\
7x=27\\
x=\dfrac{27}{7}
balu736 [363]3 years ago
3 0
5(2x-3)=3(x+4) \\
10x-15=3x+12 \\
10x-3x=12+15 \\
7x=27 \\
x=\frac{27}{7}=3 \frac{6}{7}
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If 4 sin Ф = -3 and Ф is between 0 and 360 degrees, then we conclude that Ф must be either in Quadrant III or Quadrant IV (because the sine is negative).

Let's assume we're in Quadrant IV.  Then sin Ф = opp / hyp = -3/4; that is, the opp side is negative and has length 3, and the hypo is positive 4.

According to the Pythagorean Theorem,  (-3)^2 + x^2 = 4^2, or,

x^2 = 16 - 9 = 7.

Then x is either √7 or -√7.

To find the angle Ф, use the inverse sine function:

Ф = arcsin (-3/4).  Using a calculator we get the angle -40.59 degrees, which corresponds to (360 degrees - 40.59 degrees), or 311.41 degrees.  We can check this by finding the sine of 311.41 degrees; the result is -0.75, which matches "If 4sintheta = -3."  

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