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3 years ago

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How many ways can 6 people be chosen and arranged in straight line if there are 8 people to choose from? a. 48.b. 720.c. 20, 160

.d. 40, 320.

1 answer:

Ipatiy [6.2K]3 years ago

5 0

Answer:

<h2>C. <em>20,160</em></h2>

Step-by-step explanation:

This question bothers on permutation since we are to select a some people out of a group of people and then arrange in a straight line. If r object are to be arranged in a straight line when selecting them from n pool of objects. This can be done in nPr number of ways.

nPr = n!/(n-r)!

Selection of 6 people out of 8 people can therefore be done in 8C6 number of ways.

8P6 = 8!/(8-6)!

8P6 = 8!/2!

8P6 = 8*7*6*5*4*3*2!/2!

8P6 = 8*7*6*5*4*3

8P6 = 56*360

8P6 = 20,160

<em>Hence this can be done in 20,160 number of ways</em>

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Answer:

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Step-by-step explanation:

The general for of a line is:

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In order to obtain the value of the slope ( $m$ ) we can use the corresponding slope formula:

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Now to obtain the value of $n$ you can follow two options:

You can substitute one of your points, $A$ or $B$ , in equation (3). In this way, you will obtain an equation where the variable is $n$

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See the attachment for a plot of the line.

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Step-by-step explanation:

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