Answer:
We are given that According to government data, 75% of employed women have never been married.
So, Probability of success = 0.75
So, Probability of failure = 1-0.75 = 0.25
If 15 employed women are randomly selected:
a. What is the probability that exactly 2 of them have never been married?
We will use binomial
Formula : 
At x = 2



b. That at most 2 of them have never been married?
At most two means at x = 0 ,1 , 2
So, 


c. That at least 13 of them have been married?
P(x=13)+P(x=14)+P(x=15)



Hope this helps! Let me know if you need anything!
Answer:
<h3><em>
D. 880 = 45d + 70; 18 days.</em></h3>
Step-by-step explanation:
We are given fixed monthly charge = $70.
The cost of preschool per day = $45.
Number of days = d.
Total cost of d days = cost per day × number of days + fixed monthly charge.
Therefore, we get equation
880 = 45×d+70
<h3>880 = 45d +70.</h3>
Now, we need to solve the equation for d.
Subtracting 70 from both sides, we get
880-70 = 45d +70-70
810=45d
Dividing both sides by 45, we get

18=d.
Therefore,<em> 18 days Barry attended preschool last month.</em>
<em>Therefore, correct option is D option.</em>
<h3><em>
D. 880 = 45d + 70; 18 days.</em></h3>
I think it is D
Hope my answer help you?