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3 years ago

Which expression is equivalent to (x⁻⁶/x²)³? A. 1/x B. 1/x⁵ C. 1/x⁹ D. 1/x²⁴

Mathematics

1 answer:

vovikov84 [41]3 years ago

8 0

(x⁻⁶/x²)³=(x^-6-2)^3=(x^-8)^3=x^-24=

=1/x²⁴

So the answer is variant D

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2 years ago

You have the option of buying 20 tickets at the fair for 15$ or 45 for 27$ which is te best deal

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2 years ago

Read 2 more answers

Marion bought 14 packages of plastic frog and lizard fishing lures. She bought frog lures in packages of 4 and lizard lures in p

tatuchka [14]

Answer:

Marion bought 6 frog lures and 8 lizard fishing lures.

Step-by-step explanation:

Let $f$ represent frog lures and $l$ represent lizard lures.

The total packages Marion bought is

$f+l=14...eqn1$

If she bought frog lures in packages of 4 and lizard lures in packages of 6 for a total of 72 lures, then

$4f+6l=72...eqn2$

We make $f$ the subject in equation 1 and put it into equation 2 to get;

$f=14-l...eqn3$

We put equation 3 into equation 2 to get;

$4(14-l)+6l=72$

$\Righttarrow 2(14-l)+3l=36$

We expand the bracket to get;

$28-2l+3l=36$

$-2l+3l=36-28$

$l=8$

We put $l=8$ into equation 3 to get;

$f=14-8$

$f=6$

Therefore Marion bought 6 frog lures and 8 lizard fishing lures.

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2 years ago

Question 4 options: Find the mean and standard deviation for a binomial distribution with 680 trials and a probability of succes

lys-0071 [83]

Answer:

Mean for a binomial distribution = 374

Standard deviation for a binomial distribution = 12.97

Step-by-step explanation:

We are given a binomial distribution with 680 trials and a probability of success of 0.55.

The above situation can be represented through Binomial distribution;

$P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....$

where, n = number of trials (samples) taken = 680 trials

r = number of success

p = probability of success which in our question is 0.55

So, it means X ~ $Binom(n=680, p=0.55)$

Now, we have to find the mean and standard deviation of the given binomial distribution.

Mean of Binomial Distribution is given by;

E(X) = n $\times$ p

So, E(X) = 680 $\times$ 0.55 = 374

Standard deviation of Binomial Distribution is given by;

S.D.(X) = $\sqrt{n \times p \times (1-p)}$

= $\sqrt{680 \times 0.55 \times (1-0.55)}$

= $\sqrt{680 \times 0.55 \times 0.45}$ = 12.97

Therefore, Mean and standard deviation for binomial distribution is 374 and 12.97 respectively.

3 0

3 years ago