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3 years ago

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Line A: x + y = 6 Line B: x + y = 4 Which statement is true about the solution to the set of equations? a There are infinitely m

any solutions. b There is no solution. c It is (6, 4). d It is (4, 6).

1 answer:

vovangra [49]3 years ago

3 0

Answer:

55

Step-by-step explanation:

55 is the answer I hope this helps

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Question 8 (5 points)<br> Simplify (tanx- secx) (tanx+ secx).<br> 1 <br> -1<br> sec^2xtan^2x<br> 0

Bond [772]

Answer:

-1.

Step-by-step explanation:

(tanx- secx) (tanx+ secx).

= tan^2 x + tanx sec x- tanx sec x - sec^2x

= tan^2 x - sec^2 x.

But sec^2 x = 1 + tan^2 x

so tan^2 x - sec^2 x = -1

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3 years ago

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Please help me!<br> Find WX.

Fynjy0 [20]

So WX is 7y +4 and XY is 21, and when you add those lines you get the whole thing, which is 12y so write that like an equation
12y = 7y+4+21
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5y = 25
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3 years ago

Find the length of the third side to the nearest tenth<br> 7<br> 1

AlexFokin [52]

Answer:

10.7

Step-by-step explanation:

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3 years ago

The difference between the square of two numbers is 11. Twice the square of the first number increased by the square of the seco

jeyben [28]

Answer:

Below in bold.

Step-by-step explanation:

x^2 - y^2 = 11

2x^2 + y^2 = 97

From the first equation:

y^2 = x^2 - 11

Substituting in the second equation:

2x^2 + x^2 - 11 = 97

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x^2 = 36

x = 6, -6.

Substituting for x in the first equation:

(6)^2 - y^2 = 11

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y = 5, -5.

6 0

3 years ago

Find the component form of the vector that translates P(4,5) to p'.

olga_2 [115]

Answer:

The component form of the vector P'P is $\left \langle -7, 2 \right \rangle$

Step-by-step explanation:

The component form of the vector that translates P(4, 5) to P'(-3, 7), is given as follows;

The x-component of the vector = The difference in the x-values of the point P' and the point P = -3 - 4 = -7

The y-component of the vector = The difference in the y-values of the point P' and the point P = 7 - 5 = 2

The component form of the vector P'P = $\left \langle -7, 2 \right \rangle$

6 0

3 years ago