The given expression is
And since we have x+2 common in numerator and denominator, there is a hole at x+2=0, that is at x=-2
And a function is undefined when denominator is zero. And at x=-6, denominator become zero.
So, at x=-6, the function is undefined, or there is a vertical asymptote at x=-6 and hole at x=-2 .
Similarly to the last graph that decreased, this one increases, so you have to see where the line points upwards into the right top corner
CD
Answer:
1 st questions answer is third option
while the answer of other question is 3
Step-by-step explanation:
2nd qestions explanation
put value of x=2 in equation as x-2=0 from equation
(2)^3-6(2)^2+a2+10=2
8-24+a2+10=0
2a=-18+24
2a=6
a=3
