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andre [41]
3 years ago
6

Reduce to simplest form​

Mathematics
2 answers:
Sophie [7]3 years ago
6 0

Answer:

4/15

Step-by-step explanation:

When subtracting a negative, the negatives cancel and make a positive.

-1/3 - (-3/5)

-1/3 + 3/5

Now, you have to make the fractions have common denominators.  Do this by multiplying the bottom number to get the least common multiple.  Multiply the numerator by the same number you multiplied the denominator.

(-1/3)(5/5) + (3/5)(3/3)

-5/15 + 9/15

4/15

The simplest form is 4/15.

lisov135 [29]3 years ago
3 0

Answer: 4/15

Step-by-step explanation:

-1/3 - -3/5

Two negative signs become positive so it's

-1/3+3/5

Taking the LCM as 15,

-1/3= -5/15

3/5= 9/15

-5/15 + 9/15

= (-5+9)/15

= (9-5)/15 ( just changing the order without changing the sign)

= 4/15

This is the simplest form

(If you need it in decimal form is 0.26666... or 0.267)

Hope it helps

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Assume that a driver faces the following loss distribution:Outcome Probability12,000 0.15 0 0.851. What is the expected loss?2.
xxMikexx [17]

Answer:

- 1800 ; 4284.8579 ;

Step-by-step explanation:

Given the table :

Outcome _____ probability

-12000 ________ 0.15

__ 0 __________ 0.85

Expected loss, m: Σx*p(x)

(-12000 * 0.15) + (0 * 0.85)

-1800 + 0 = - 1800

Standard deviation = sqrt(Var(x))

Var(x) = Σx²*p(x) - m²

(-12000^2 * 0.15) + (0^2 * 0.85)] - 1800^2

21,600,000 - 3240000

= 18360000

Standard deviation = sqrt(18360000)

Standard deviation = 4284.8579

3 0
2 years ago
What is the horizontal asymptote of the rational function f(x) = 3x / (2x - 1)?
-BARSIC- [3]

Answer:

Step-by-step explain

Find the horizontal asymptote for f(x)=(3x^2-1)/(2x-1) :

A rational function will have a horizontal asymptote of y=0 if the degree of the numerator is less than the degree of the denominator. It will have a horizontal asymptote of y=a_n/b_n if the degree of the numerator is the same as the degree of the denominator (where a_n,b_n are the leading coefficients of the numerator and denominator respectively when both are in standard form.)

If a rational function has a numerator of greater degree than the denominator, there will be no horizontal asymptote. However, if the degrees are 1 apart, there will be an oblique (slant) asymptote.

For the given function, there is no horizontal asymptote.

We can find the slant asymptote by using long division:

(3x^2-1)/(2x-1)=(2x-1)(3/2x+3/4-(1/4)/(2x-1))

The slant asymptote is y=3/2x+3/4

6 0
3 years ago
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It would be the top one
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notsponge [240]

Answer:

21

Step-by-step explanation:

f(x) = 2x^2 + 3

f(-3) = 2(-3)^2 + 3

f(-3) = 2(9) + 3

f(-3) = 18 + 3

f(-3) = 21

6 0
3 years ago
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Fittoniya [83]

Answer:

180

Step-by-step explanation:

Base x Height

So 9 x 20 to get 180

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