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Strike441 [17]
3 years ago
5

Chris purchased two uniforms for his new job. He was given a $5 discount on the total purchase for being a new employee. If he s

pent $95, what was the original cost per uniform?
Mathematics
1 answer:
telo118 [61]3 years ago
6 0
The original cost was $50 per uniform
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9. What is the Greatest Common Factor (GCF) of 9 and 12? *<br> 108<br> о<br> O 36<br> o<br> 9<br> 3
Simora [160]

Answer:

3

Step-by-step explanation:

We found the factors and prime factorization of 9 and 12. The biggest common factor number is the GCF number. So the greatest common factor 9 and 12 is 3.

Hope this helps!

6 0
3 years ago
Athlon and a-series processors manufactured by amd are not x86 compatible.​ false true
Y_Kistochka [10]
False. Btw this is a computer and technology question not a mathematic question
5 0
3 years ago
Find the sum of the smallest 7- digit number and largest 4-digit number​
Snowcat [4.5K]

1009999

Hope it helps you...

7 0
3 years ago
BRAINLIEST IF CORRECT!! Which property of equality would you use to solve
shusha [124]

Answer:

0.4

Step-by-step explanation:

14x = 35 \\  \div b \: s \: y \: 14 \\ 14x \div 14 = 35 \div 14 \\ x = 0.4

4 0
3 years ago
PLZ HELP, AND PLZ EXPLAIN
shutvik [7]

Answer:

C

Step-by-step explanation:

To make it easy let's start by organizing our information :

  • AC=12 AND BD=8
  • ABCD is a rhombus
  • K and L are the midpoints of sides AD and CD
  • we notice that the rhombus ABCD is divided into four right triangles

What do you think of when you hear a right triangle ?

  • The pythagorian theorem !

AC and BD  are khown so let's focus on them .

If we concentrated we can notice that AB and BD are cossing each other in the midpoints . why ?

Simply because they are the diagonals of a rhombus .

ow let's apply the pythagorian theorem :

  • (AC/2)² + (BD/2)² = BC²
  • 6²+4²=52
  • BC²= 52⇒\sqrt{52}=BC

Now we khow that : AB=BC=CD=AD=\sqrt{52}

This isn't enough . Let's try to figure out a way to calculate the length of KL  wich is the base of the triangle

  • KL is parallel to AC
  • k is the midpoint of AD and L of DC

I smell something . yes! Thales theorem

  • KL/AC=DL/DC=DK/AD WE4LL TAKE OLY ONE
  • KL/12=\sqrt{52}/2*\sqrt{52}  
  • KL/12=1/2⇒ KL=6

Now we have the length of the base kl

Now the big boss the height :

  • notice that you khow the length of KL
  • BD crosses kl from its midpoint and DL = \sqrt{52} /2

What I want to do is to apply the pythgorian thaorem to khow the lenght of that small part that is not a part of the height of the triangle . I will call it D

  • DL²=(KL/2)²+D²
  • 52/4= 9+ D²
  • D² = 52/4-9 +4 SO D=2

now the height of the trigle is H= BD-D= 8-2=6

NOw the area of the triangle is :

  • A=(KL*H)/2 ⇒ A= (6*6)/2=18

THE ANSWER IS 18 SQ.UN

5 0
3 years ago
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