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2 years ago

Find the equations of a line through these 2 points

Mathematics

1 answer:

stiv31 [10]2 years ago

4 0

answer is 2.2 66 88862 u88272

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Which example describes area

Aleks [24]

I believe C. Measuring the length from one end of the field tot he other would be the most reasonable answer, because Area = Length x Width

6 0

3 years ago

The population in a city was 40,000.00. The population rose p

Svetach [21]

Answer:P+41,700

Step-by-step explanation:40000-3000=37000.

37000+4700=41,700

5 0

3 years ago

Read 2 more answers

A data set consists of the values 2, 6, 3, and 1. If we consider this a population (all the values available), the variance isA.

Hoochie [10]

Answer: E. none of the above

Step-by-step explanation:

The given data values that represents the population:

2, 6, 3, and 1.

Number of values : n=4

Mean of the data values = $\dfrac{\text{Sum of values}}{\text{No. of values}}$

$\dfrac{2+6+3+1}{4}=\dfrac{12}{4}=3$

Sum of the squares of the difference between each values and the mean =

$(2-3)^2+(6-3)^2+(3-3)^2+(1-3)^2$

$=-1^2+3^2+0^2+(-2)^2$

$=1+9+0+4=14$

Now , Variance = (Sum of the squares of the difference between each values and the mean ) ÷ (n)

= (14) ÷ (4)= 3.5

Hence, the variance is 3.5.

Therefore , the correct answer is "E. none of the above".

8 0

3 years ago

What is the equation of the line that passes through the point (5,0) and has slope of 2/5

aniked [119]

Answer:
Y=2/5x-2

Explanation:

4 0

2 years ago

Read 2 more answers

A boutique handmade umbrella factory currently sells 37500 umbrellas per year at a cost of 7 dollars each. In the previous year

slega [8]

Answer:

$302,500

Step-by-step explanation:

If cost (C) = $7, then Sales (S) = 37,500 units

If cost (C) = $15, then Sales (S) = 17,500 units

The slope of the linear relationship between units sold and cost is:

$m=\frac{37,500-17,500}{7-15}\\m= -2,500$

The linear equation that describes this relationship is:

$s-s_0 =m(c-c_0)\\s-17500 =-2500(c-15)\\s(c)=-2500c + 55,000$

The revenue function is given by:

$R(c) = c*s(c)\\R(c)=-2500c^2 + 55,000c$

The cost at which the derivative of the revenue equals zero is the cost that yields the maximum revenue.

$\frac{d(R(c))}{dc}=0 =-5000c + 55,000\\c=\$11$

The optimal cost is $11, therefore, the maximum revenue is:

$R(11)=-2500*11^2 + 55,000*11\\R(11)=\$ 302,500$

4 0

3 years ago