Find the equations of a line through these 2 points
1 answer:
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Answer:
Step-by-step explanation:
If the shape is a parallelogram, that means the two parallel sides are equal in length so, we get the equation:
After solving for x and y, we get that
x = 23 and y = 95
Hope that helps!
Answer:
<em>First option: </em>
Step-by-step explanation:
Given the point-slope equation , you need to solve for
, because you are looking for the equation of the line in slope-intercept form:
Being the slope of that line, and
the intersection of the line with the y-axis.
Then:
Apply Distributive property:
Subtract 7 from both sides:
Rewrite the equation:
(The linear function of the First option)
Answer:
6√3 ±3 ≈ {7.392, 13.392}
Step-by-step explanation:
The length of AB is the long side of a right triangle with hypotenuse CD and short side (AC -BD). The desired radius values will be half the length of EF, with AE added or subtracted.
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<h3>length of AB</h3>Radii AC and BD are perpendicular to the points of tangency at A and B. They differ in length by AC -BD = 12 -9 = 3 units.
A right triangle can be drawn as in the attached figure, where it is shaded and labeled with vertices A, B, C. Its long leg (AB in the attachment) is the long leg of the right triangle with hypotenuse 21 and short leg 3. The length of that leg is found from the Pythagorean theorem to be ...
AB = √(21² -3²) = √432 = 12√3
<h3>tangent circle radii</h3>This is the same as the distance EF. Half this length, 6√3, is the distance from the midpoint of EF to E or F. The radii of the tangent circles to circles E and F will be (EF/2 ±3). Those values are ...
6√3 ±3 ≈ {7.392, 13.392}
