Answer:
Step-by-step explanation:
Given that in a study of computer use, 1000 randomly selected Canadian Internet users were asked how much time they spend using the Internet in a typical week (Ipsos Reid, August 9, 2005). The mean of the sample observations was 12.7 hours.
a)
(right tailed test at 5% level)
test statistic Z = Mean diff/std error = 1.265
(Here z test is used because sigma is known)
p value = 0.103
Since p >0.05, we accept H0
b) Here s= 2 hours.
But sample size is very large so z test is used.
Std error =
Test statistic = 3.16
p value =0.000783
since p <alpha, H0 is rejected
c) Because std deviation was less in part B, we got p value very low thus making us reject H0 in part B.