CAN SOMEONE PLEASE HELP ME WITH THIS QUESTION AND PLEASE SHOW WORK. ASAP
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Refer to the attachment.
Answer:
1/2
Step-by-step explanation:
A sample space is a collection or a set of possible outcomes of a random experiment.
I have created the sample space for these data and attached it. As you can see there are 16 possible outcomes.
To find the probability that the total showing is greater than 9, simply identify the number of values in the sample space that are greater than 9.
(I have highlighted these in yellow).
Therefore, P(X>9) = 8/16 = 1/2
Answer:
1) Domain: { 1,2,3,4,5,6}
Range: {12,24,36,48,60,72}
2) First four terms are: 2,5,8,11
3) First four terms are: 8,13,20,29
4) First four terms are: 0,0,2,6
5) First four terms are: 0,1,1.41,1.73
Step-by-step explanation:
1.
n 1 2 3 4 5 6
f(n) 12 24 36 48 60 72
Domain: { 1,2,3,4,5,6}
Range: {12,24,36,48,60,72}
Write first four terms of each sequence
2) f(n)=3n-1
Put n = 1, 3(1)-1 = 3-1 = 2
Put n = 2, 3(2)-1 = 6-1 = 5
Put n = 3, 3(3)-1 = 9-1 = 8
Put n = 4, 3(4)-1 = 12-1 = 11
So, First four terms are: 2,5,8,11
3) f(n)=n^2+2n+5
Put n = 1, (1)^2+2(1)+5= 1+2+5 = 8
Put n = 2, (2)^2+2(2)+5 = 4+4+5= 13
Put n = 3, (3)^2+2(3)+5 = 9+6+5 = 20
Put n = 4, (4)^2+2(4)+5 = 16+8+5 = 29
So, First four terms are: 8,13,20,29
4) f(n)=(n-1)(n-2)
Put n = 1, (1-1)(1-2) = 0(-1) = 0
Put n = 2, (2-1)(2-2) = 1(0) = 0
Put n = 3, (3-1)(3-2) = 2(1) = 2
Put n = 4, (4-1)(4-2) = 3(2) = 6
So, First four terms are: 0,0,2,6
5) f(n) =
Put n=1
Put n=2
Put n=3
Put n=4
So, First four terms are: 0,1,1.41,1.73