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4 years ago

What is -18/-6? I am having trouble with negative numbers.

Mathematics

2 answers:

dolphi86 [110]4 years ago

7 0

Answer:

1.125

Step-by-step explanation:

The symbol " / " is a Divide expression. If you divide both negative or add, subtract and multiply, the anwer will be positive.

-18/-16 =

Exact Form :

9/8

Decimal Form :

1.125

Mixed Number Form:

1 1/8

8_murik_8 [283]4 years ago

3 0

Answer:

Step-by-step explanation:

This is a simple rule with negative numbers, a negative divided by a negative is negative. So, 18/6 is 3, so the answer is 3

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Find the equation of the line with that passes through the

nadya68 [22]

Answer: y = -1

Step-by-step explanation:

Use the slope formula and slope-intercept form y=mx+b to find the equation

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3 years ago

Write 2.37 as a percent.

Alenkasestr [34]

237% move the decimal twice

6 0

3 years ago

Which expression simplifies...

Zina [86]

Answer:

see below

Step-by-step explanation:

If suffices to look at the last term. It must simplify to 4/(3w²), so the exponents of z must match in numerator and denominator, and the ratio of constants must reduce to 4/3.

The exponents of z have the right values in choices B and D, but the ratio of constants only matches in choice D. Looking at the rest of choice D, we see that we can factor 6w²z² from both numerator and denominator, then factor 2 from the remaining numerator to make it match the desired form.

$\dfrac{(12w^2z^4-24w^2z^2)}{18w^4z^2}=\dfrac{6w^2z^2}{6w^2z^2}\cdot\dfrac{2z^2-4}{3w^2}=\dfrac{2(z^2-2)}{3w^2}$

3 0

3 years ago

Triangle QRS has vertices Q(-4,2),R(3,0), and S(4,3).

Dafna1 [17]

The coordinates of the vertices of $\triangle Q'R'S'$ are $Q'(x,y) = (0, -4)$ , $R'(x,y) = (7,-6)$ and $S'(x,y) = (8, -3)$ , respectively.

Vectorially speaking, a point is translated to another location on Cartesian plane by means of this expression:

$A'(x,y) = A(x,y) + T(x,y)$ (1)

Where:

$A(x,y)$ - Original point.
$A'(x,y)$ - Translated point.
$T(x,y)$ - Translation vector.

If we know that $Q(x,y) = (-4,2)$ , $R(x,y) = (3,0)$ , $S(x,y) = (4, 3)$ and $R'(x,y) = (7, -6)$ $T(x,y) = (4, -6)$ , then the coordinates of the vertices of the triangle $Q'R'S'$ are:

$Q'(x,y) = Q(x,y) + T(x,y)$

$Q'(x,y) = (-4,2) + (4,-6)$

$Q'(x,y) = (0, -4)$

$R'(x,y) = R(x,y) + T(x,y)$

$R'(x,y) = (3,0) +(4,-6)$

$R'(x,y) = (7,-6)$

$S'(x,y) = S(x,y) + T(x,y)$

$S'(x,y) = (4, 3) + (4, -6)$

$S'(x,y) = (8, -3)$

The coordinates of the vertices of $\triangle Q'R'S'$ are $Q'(x,y) = (0, -4)$ , $R'(x,y) = (7,-6)$ and $S'(x,y) = (8, -3)$ , respectively.

We kindly invite to see this question on translations: brainly.com/question/17485121

5 0

3 years ago

On a graph with y-values ranging from 1,013,020 to 9,618,115, what is a reasonable scale to use on a y-axis with 10 tick marks?

Travka [436]

Divide the range range between 10 fo find the appropriate scale.

[9618115 - 1013020]/10 = 8605095/10 = 860509.5

Then use scale 1: 1000000. So your marks will be

1 = 1000000
2 = 2000000
3 = 3000000

... 10 = 10000000

8 0

3 years ago