Question

Triangle QRS has vertices Q(-4,2),R(3,0), and S(4,3).

Answer 1

The coordinates of the vertices of $\triangle Q'R'S'$ are $Q'(x,y) = (0, -4)$, $R'(x,y) = (7,-6)$ and $S'(x,y) = (8, -3)$, respectively.

Vectorially speaking, a point is translated to another location on Cartesian plane by means of this expression:

$A'(x,y) = A(x,y) + T(x,y)$ (1)

Where:

• $A(x,y)$ - Original point.
• $A'(x,y)$ - Translated point.
• $T(x,y)$ - Translation vector.

If we know that $Q(x,y) = (-4,2)$, $R(x,y) = (3,0)$, $S(x,y) = (4, 3)$ and $R'(x,y) = (7, -6)$$T(x,y) = (4, -6)$, then the coordinates of the vertices of the triangle $Q'R'S'$ are:

$Q'(x,y) = Q(x,y) + T(x,y)$

$Q'(x,y) = (-4,2) + (4,-6)$

$Q'(x,y) = (0, -4)$

$R'(x,y) = R(x,y) + T(x,y)$

$R'(x,y) = (3,0) +(4,-6)$

$R'(x,y) = (7,-6)$

$S'(x,y) = S(x,y) + T(x,y)$

$S'(x,y) = (4, 3) + (4, -6)$

$S'(x,y) = (8, -3)$

The coordinates of the vertices of $\triangle Q'R'S'$ are $Q'(x,y) = (0, -4)$, $R'(x,y) = (7,-6)$ and $S'(x,y) = (8, -3)$, respectively.

We kindly invite to see this question on translations: brainly.com/question/17485121