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Sedbober [7]
3 years ago
8

Write 13 1/5 as a decimal. ​

Mathematics
2 answers:
erma4kov [3.2K]3 years ago
8 0
13.2 ................ 13x1 then divide it to 5
Alexxandr [17]3 years ago
3 0

Answer:

13.2

Step-by-step explanation:

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If the standard deviation of a population increases what else must necessarily increase
Verdich [7]
The *standard error* must also increase if the standard deviation of a population increases.
6 0
3 years ago
Evaluate<br> 5-(2w-8)=6w-9
Brilliant_brown [7]

Step-by-step explanation:

Steps

5−(2w−​8)=6w−9

Show Steps

Expand 5−(2w−8):    −2w+13

−2w+13=6w−9

Subtract 13 from both sides

−2w+13−13=6w−9−13

Simplify

−2w=6w−22

Subtract 6w from both sides

−2w−6w=6w−22−6w

Simplify

−8w=−22

Divide both sides by −8

−8w

−8 =

−22

−8

Show Steps

Simplify

w=​

11

4

click her

5 0
3 years ago
What is the best approximate solution of the system of linear equations y=1.5x-1 and y=1
krek1111 [17]
If there is a solution, y=y so we can say:

1.5x-1=1  add 1 to both sides

1.5x=2  divide both sides by 1.5

x=2/1.5

x=4/3  (exact)

x=1 1/3 (exact)

x≈1.33 (to nearest hundredth of a unit)

7 0
4 years ago
Which of the following questions are true statements about the expression 6+(-6)
Darina [25.2K]
What r the following questions?
5 0
4 years ago
What is the solution of -8/2y-8=5/y+4-7y+8/y^2-16
Mnenie [13.5K]
<h2>Answer:</h2>

The solution of the given equation is:

                         y=6

<h2>Step-by-step explanation:</h2>

The expression is given by:

\dfrac{-8}{2y-8}=\dfrac{5}{y+4}-\dfrac{7y+8}{y^2-16}

Now on solving for the given equation

\dfrac{-8}{2(y-4)}=\dfrac{5}{y+4}-\dfrac{7y+8}{(y-4)(y+4)}

since,

a^2-b^2=(a-b)(a+b)\\\\so,\\\\y^2-16=y^2-4^2\\\\i.e.\\\\y^2-16=(y-4)(y+4)

Hence, we get:

\dfrac{-4}{y-4}=\dfrac{5\times (y-4)-(7y+8)}{(y+4)(y-4)}\\\\i.e.\\\\\dfrac{-4}{y-4}=\dfrac{5y-20-7y-8}{(y-4)(y+4)}

-4\times (y-4)(y+4)=(-2y-28)(y-4)\\\\i.e.\\\\(y-4)(-4\times (y+4))=(-2y-28)(y-4)\\\\i.e.\\\\(y-4)(-4y+16)=(-2y-28)(y-4)\\\\i.e.

(y-4)(-4y+16)-(-2y-28)(y-4)=0\\\\i.e.\\\\(y-4)(-4y-16+2y+28)=0\\\\i.e.\\\\(y-4)(-2y+12)=0\\\\i.e.

y-4=0\ or\ -2y+12=0\\\\i.e.\\\\y=4\ or\ 2y=12\\\\i.e.\\\\y=4\ or\ y=6

but y≠ 4

since, the denominator of the term in the left side of the given equality and the second term in the right side of the given equality will be zero and hence, the expression will be not defined.

Hence, the value of y is: 6

7 0
3 years ago
Read 2 more answers
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