3 years ago

1.) 3(x + 7) - 9x (x = 1

Mathematics

1 answer:

MrMuchimi3 years ago

7 0

Answer:

bonjour voilà la réponse 4.55

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Prove that if a and b are integers, then a^2-4b egal or non-egal 2

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Answer:

tex]a^2 - 4b \neq 2[/tex]

Step-by-step explanation:

We are given that a and b are integers, then we need to show that $a^2 - 4b \neq 2$

Let $a^2 - 4b = 2$

If a is an even integer, then it can be written as $a = 2c$ , then,

$a^2 - 4b = 2\\(2c)^2 - 4b =2\\4(c^2 -b) = 2\\(c^2 -b) =\frac{1}{2}$

RHS is a fraction but LHS can never be a fraction, thus it is impossible.

If a is an odd integer, then it can be written as $a = 2c+1$ , then,

$a^2 - 4b = 2\\(2c+1)^2 - 4b =2\\4(c^2+c-b) = 2\\(c^2+c-b) =\frac{1}{4}$

RHS is a fraction but LHS can never be a fraction, thus it is impossible.

Thus, our assumption was wrong and $a^2 - 4b \neq 2$ .

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3 years ago

1.) 3(x + 7) - 9x (x = 1​

1.) 3(x + 7) - 9x (x = 1