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Simora [160]
3 years ago
7

Name an angle with vertex n that appears obtuse

Mathematics
1 answer:
UNO [17]3 years ago
3 0
Idk ffdssijsjsjsjsjsjsjsjs
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Here is the graph of the sequence M define M recursively using function notation<br> 
aev [14]

The graph of the sequence M , we define M recursively using function notation

f(n+1)=f(n)-2

Given :

the graph of the sequence M

Lets write the recursive function using the given points

First point is (1,7) and second point is (2,5) then (3,3) and so on

For recursive function , we use the initial point (1,7)

when n=1, f(n)=7

the y values of the point are decreasing by 2. Common difference is -2

Recursive function is

f(n+1)=f(n)-diffeference \\f(n+1)=f(n)-2

where n=2,3,4...

Learn more : brainly.com/question/10676131

8 0
2 years ago
Find the inverse of the relation. Use proper notation. {(8,−1),(−8,−1),(−2,−8),(2,8)} please help!!
tiny-mole [99]

Answer: The inverse relation is { (-1, -8), (-1, -8), (-8, -2), (8, 2) }

The inverse is effectively the opposite of the original relation. It undoes what the original relation does. So we'll swap the x and y values for each given point in the form (x,y). Something like (8,-1) becomes (-1,8). The other points follow the same pattern as well.

6 0
3 years ago
= 9x2 +9x -18,/<br> 3x +6
Ede4ka [16]

Answer:24+3x

Step-by-step explanation:

maybee i just used photomath

3 0
3 years ago
Choose the best answer:
Oksi-84 [34.3K]

Answer:

The length of the hypotenuse is 2 square root of 13 ⇒ c

Step-by-step explanation:

The rule of the area of the right triangle is A = \frac{1}{2} × leg1 × leg2, where

leg1 and leg2 are the sides of the right angle

∵ The area of a right triangle is 12 in²

∵ The ratio of the length of its legs is 2: 3

→ Let leg1 = 2x and leg2 = 3x

∵ leg1 = 2x and leg2 = 3x

→ Substitute them in the rule of the area above

∴ 12 = \frac{1}{2} × 2x × 3x

∵ 2x × 3x = 6x²

∴ 12 =  \frac{1}{2} × 6x²

∴ 12 = 3x²

→ Divide both sides by 3 to find x²

∴ 4 = x²

→ Take √ for both sides

∴ x = 2

→ Substitute x in the expressions of leg1 and leg2 to find them

∴ leg1 = 2(2) = 4 inches

∴ leg2 = 3(2) = 6 inches

∵ hypotenuse = \sqrt{(leg1)^{2}+(leg2)^{2}}

∴ hypotenuse = \sqrt{(4)^{2}+(6)^{2}}=\sqrt{16+36}=\sqrt{52}

∵ The simplest form of \sqrt{52} = 2\sqrt{13}

∴ The length of the hypotenuse = 2\sqrt{13} inches

3 0
3 years ago
12) 251 students went on a field trip. Six
lbvjy [14]

Answer:

38 students

Step-by-step explanation:

251 students minus the students traveled in cars =228 divide that by six buses and your outcome will be 38 students

3 0
3 years ago
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