At one university, the students are given z-scores at the end of the each semester, rather than the traditional gpas. the mean a nd standard deviation of all students' cumulative gpas, on which the z-scores are based, are 2.7 and 0.5, respectively
1 answer:
<span>a) 2=(x-2.7)/.5 (2)(.5) = x-2.7 1=x-2.7 x=3.7 -2.5=(x-2.7)/.5 (-2.5)(.5) = x-2.7 -1.25 =x-2.7 x=2.7-1.25 = 1.45 b) 95% of the students' score lie within 2 standard deviation of the mean. Therefore, the top 2.5% corresponds to a z value of 2. The limits are (2, infinity) --- top 2.5 %</span>
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