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BabaBlast [244]
2 years ago
8

Janet can plant nine feet of carrots in 15 minutes while her daughter Amy can plant 17 feet of carrots in half an hour.

Mathematics
1 answer:
Lena [83]2 years ago
6 0

Answer:

Step-by-step explanation:

In order to find who is more efficient at planting carrots, we want to put both ratios in terms of the same amount of time.

For simplicity, lets see how many carrots each can make in 1 hour.

Janet:\\9ft \: in \: 15 \:minutes

\frac{9ft}{15min} = \frac{xft}{60min}\\x = \frac{60*9}{15} = 36

Janet can plant 36 feet of carrots in one hour

Amy:\\\frac{17ft}{30min} = \frac{xft}{60min}\\x = \frac{17*60}{30} = 34

Amy can plant 34 feet of carrots in one hour

So, Janet can plant carrots more quickly

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2 years ago
What is the solution set of the inequality: 14- 3x < -1
Kazeer [188]

Answer:

<h2>x>5 (Answer should have a positive sign.)</h2>

Step-by-step explanation:

To solve this problem, isolate x from one side of the equation.

First, subtract by 14 from both sides.

14-3x-14<-1-14

Solve.

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Multiply by -1 from both sides.

(-3x)(-1)>(-15)(-1)

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3x/3>15/3

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In conclusion, final answer is x>5.

3 0
3 years ago
Find the LCM of 4 and 9<br><br> A. 9<br> B. 35<br> C. 72<br> D. none of the above
Vitek1552 [10]
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7 0
3 years ago
Read 2 more answers
Help needed plez<br><br>Ans in (ii) is 1.5
Deffense [45]
OK first let's check the x=1.5. 

y = \frac x 6 (x^2 - 10)

y = 1-2x

1-2x = \frac x 6 (x^2 - 10)

6-12x = x^3 - 10 x

x^3 + 2x-6 = 0

Oh my, that's called a depressed cubic, no x^2 term. There's a formula for these very much like the quadratic formula but you're probably not quite old enough for that.  Anyway, x\approx 1.45616 \approx 1.5 is a solution, but that's not what they're asking.  They are asking us to compare 

x^3 + 2x-6 = 0

with

x^3 + bx^2 + cx + d = 0

and conclude b=0, c= 2, d=-6

It turns out we did need all the rest of it.  Save those brain cells, there's lots more math coming.


~~~~~~~~~~~~~~

I love it when the student asks for more.  Here's the formula for a depressed cubic. I won't derive it here (though I did earlier today, coincidentally, but I'm probably not allowed to link to my Quora answer "what led to the discovery of complex numbers" from here).  We use the trick of putting coefficients on the coefficients to avoid fractions.

x^3 + 3 p x = 2 q

has solutions

x = \sqrt[3] { q - \sqrt{p^3 + q^2} } + \sqrt[3] {q + \sqrt{p^3 + q^2} } &#10;&#10;


That's pretty simple, though sometimes we end up having to take the cube roots of complex numbers, which isn't that helpful.  Let's try it out on


x^3 + 2x=6


That's p=2/3, q=3 so

x = \sqrt[3] { 3 - \sqrt{(2/3)^3+9} } + \sqrt[3] {3 + \sqrt{(2/3)^3+9} }

x = \sqrt[3] { 3 - \sqrt{753}/9 } +\sqrt[3]{3 + \sqrt{753}/9 }

x \approx 1.4561642461359084609748069666






6 0
3 years ago
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